A boy stands on a fishing pier and tosses a pebble into a pond. The pebble is thrown from a height of 2.50 m above the water surface with a velocity of 4.50 m/s at an angle of 60.0° above the horizontal. As the pebble strikes the water surface, it immediately slows down to exactly half the speed it had when it struck the water and maintains that speed while in the water. After the pebble enters the water, it moves in a straight line in the direction of the velocity it had when it struck the water. If the pond is 4.60 m deep, how much time elapses (in s) between when the pebble is thrown and when it strikes the bottom of the pond?

Q: PLEASE CHECK YOUR ANSWER 3 or 4 TIMES THE PREVIOUS TUTOR GOT IT WRONG!!!! And please make the answer…

A: Given:Initial speed of the projectile = 47.6 m/sAngle of projectile = 44.2oTime taken = 1.50 s

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A: Initial velocity (u) = 11 msAngle (θ) = 46oheight above the ground (h) = 1.80 m

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A:

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A: In this question we have to determine the initial velocity, range and total time for the projectile.…

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A:

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A:

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A: H = 30 m initial velocity = 20 m/s projection = horizontal angle of projection = 0o

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A:

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Projectile Motion