A bullet of mass 90 grams, traveling at 120 m/sec, strikes a stationary aluminum block ( M = 3.00 kg ) and penetrates through the block with the velocity of 40 m/sec, M (Before) (After)! m Vo T!!!!!!! 13. find the velocity of the block after the collision. a. 3.60 m/s b. 3.50 m/s c. 4.80 m/s V ZZO-V d. 2,40 m/s 1177

University Physics Volume 1
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Chapter9: Linear Momentum And Collisions
Section: Chapter Questions
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A bullet of mass 90 grams, traveling at 120 m/sec, strikes a stationary aluminum block ( M = 3.00 kg)
and penetrates through the block with the velocity of 40 m/sec,
(Before)
(After) M
m
T
Vo
13. find the velocity of the block after the collision.
a. 3.60 m/s
b. 3.50 m/s
c. 4.80 m/s
V
MO
d. 2.40 m/s
14. find the percent energy loss during collision : by taking the difference and divided by initial kinetic energy.
c. 88 %
a. 72 %
b. 86%
d. 75 %
Transcribed Image Text:A bullet of mass 90 grams, traveling at 120 m/sec, strikes a stationary aluminum block ( M = 3.00 kg) and penetrates through the block with the velocity of 40 m/sec, (Before) (After) M m T Vo 13. find the velocity of the block after the collision. a. 3.60 m/s b. 3.50 m/s c. 4.80 m/s V MO d. 2.40 m/s 14. find the percent energy loss during collision : by taking the difference and divided by initial kinetic energy. c. 88 % a. 72 % b. 86% d. 75 %
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