A car starts from 2.0 m/s and accelerates at 4.0 m/s2 for 6.0 s, it coasts for 5.0 s, and then slows down at a rate of 2.0 m/s2 to a stop. How far has it traveled, in meters?Your answer needs to have 3 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in thequestion statement.

Initial velocity of a car u=2 m/s Acceleration of car a= 4 m/s2 Time period when car travel = 6 s…

Answered: A car starts from 2.0 m/s and…

A car starts from 2.0 m/s and accelerates at 4.0 m/s2 for 6.0 s, it coasts for 5.0 s, and then slows down at a rate of 2.0 m/s2 to a stop. How far has it traveled, in meters?

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter1: Getting Started

Section: Chapter Questions

Problem 18PQ: Acceleration a has the dimensions of length per time squared, speed v has the dimensions of length...

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Concept explainers

Distance and Speed

The speed, distance and time relation forms the basis of study of motion. You will need these concepts in the study of Mechanics. This concept is applicable for students who are studying the following courses –

Question

A car starts from 2.0 m/s and accelerates at 4.0 m/s2 for 6.0 s, it coasts for 5.0 s, and then slows down at a rate of 2.0 m/s2 to a stop. How far has it traveled, in meters?
Your answer needs to have 3 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the
question statement.

Expert Solution

Step 1

Initial velocity of a car u=2 m/s

Acceleration of car a= 4 m/s²

Time period when car travel = 6 s

We know the expression for newton 2nd law

$s = ut + \frac{1}{2} {at}^{2}$

For first 6 second the car travel

$s_{1} = ut + \frac{1}{2} {at}^{2} s_{1} = (2 \times 6) + \frac{1}{2} \times 4 \times 6^{2} s_{1} = 84 m$

We know the expression to calculate velocity after 6 s

$v = u + at v = 2 + 4 \times 6 v = 26 m / s$

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