A closely coiled helical spring is made of 6 mm wire. The maximum shear stress and deflection under a 200 N load is not to exceed 80 MPa and 11 mm respectively. Determine the no. of coils and their mean diameter. Take C = 84 MPa.
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- Solve the preceding problem (W 250 × 44.8) if the resultant force P equals 110 kN and E = 200 GPa.Solve the preceding problem if the cross- sectional dimensions are b = 1.5 in. and h = 5.0 in., the gage angle is ß = 750, the measured strains are = 209 × 10-6 and B = -110 × 10, and the material is a magnesium alloy with modulus E = 6.0 X 106 psi and Poisson’s ratio v = 0.35.A statically indeterminate stepped shaft ACE is fixed at ends A and B and loaded by a torque TQat point C (see figure). The two segments of the bar are made of the same material, have lengths L4and LB, and have polar moments of inertia IAand Ipb. Determine the angle of rotation 4>of the cross section at Cby using strain energy. Hint: Use Eq, (3-55b) to determine the strain energy Urn terms of the angle d?. Then equate the strain energy to the work done by the torque to. Compare your result with Eq. (3-52) of Example 3-9.
- A spring sustains 200 ft-lb of energy with a deflection of 3’’. Assume that the mean coil diameter is 7 times the wire diameter and that the allowable stress is 100ksi. Determine the wire diameter.Two coaxial closed coil springs make up a standard compound helical spring. When both springs are unloaded, they are not of equal length. If each spring's working stress is to be the same. The wire material has an 80 GPa modulus of rigidity. Find the diameter of steel wire for inner spring and stiffness of inner spring. Also find the stiffness of the compound spring. Outer spring a: Mean coil diameter = 100 mm No. of turns = 15 Wire diameter = 12.5 mm Inner spring b: mean coil diameter = 75 mm No. of turns = 20A closely coiled helical spring is made of 6 mm wire. The maximum shear stress and deflection under a 200 N load is not to exceed 80 MPa and 11 mm respectively. Determine the no. of coils and their mean diameter. Take C = 84MPa .
- A composite spring consists of two close-coil helical springs connected in series. Each spring has 14 coils at a mean diameter of 20 mm. The stiffness of the composite spring is 800 N/m. If the wire diameter of one spring is 2.5 mm, find the wire diameter of the other. What will be the maximum load which can be carried by the composite spring and the Take G=78 GPa. corresponding deflection for maximum shear stress of 150 MPa?An open coiled heilcal spring made of 6 mm diam- eter steel wire and 60 mm mean coil diameter, with 60° inclination of the coils with the spring axis, is subjected to an axial torque T. If 1 number of turns in the spring increases by and original number of 8 turns is 12, calculate : (a) Magnitude of axial torque T, and (b) Change in axial length of the spring. Take E = 210 GPa and G = 84 GPa.A machinery uses a helical tension spring with wire diameter of 3 mm and coil outside diameter of 35 mm. The spring has 9 total coils. The design shear stress is 500 MPa and the modulus of rigidity is 82 GPa. Determine the force that causes the body of the spring to its shear stress in N. Consider ground ends.
- A close-coiled helical spring is made of a wire of diameter 20 mm. The mean radius of the coils is 100 mm. Find the number of turns required and the maximum axial load permissible if the shear stress is not to exceed 100 MPa and the maximum elongation is limited to 40 mm. G = 83 GPa.A simple torsion-bar spring is shown. The shear stress in the steel [G = 11,500 ksi] shaft is not to exceed 10000 psi, and the vertical deflection of joint D is not to exceed 0.650 in. when a load of P = 4500 lb is applied. Neglect the bending of the shaft and assume that the bearing at Callows the shaft to rotate freely. Determine the minimum diameter required for the shaft. Use dimensions of a = 84 in., b = 36 in., and c = 34 in. Answer: d= i a D P B in. b CA simple torsion-bar spring is shown. The shear stress in the steel [G= 11,500 ksi] shaft is not to exceed 10800 psi, and the vertical deflection of joint D is not to exceed 0.425 in. when a load of P = 3100 lb is applied. Neglect the bending of the shaft and assume that the bearing at C allows the shaft to rotate freely. Determine the minimum diameter required for the shaft. Use dimensions of a = 84 in., b = 32 in., and c = 36 in. Part 1 Answer: T = a i D P B Calculate the torque being applied to the shaft at point B. b C lb-in