A common year in the modern Gregorian Calendar consists of 365 days. In reality, Earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines the number of days in February for that year. Ex: If the input is: 1712 the output is: 1712 has 29 days in February. Ex: If the input is: 1913 the output is: 1913 has 28 days in February. Your program must define and call the following function. The function should return the number of days in February for the input year. int DaysInFeb (int userYear) 378260.2498516 qudzay? LAB LAB: Leap year - functions АCTIVITY main.c Load default template. 1 #include 2 #include 3 4 int DaysInFeb (int userYear) { if( userYear % 400 -- 0) return true; 7 else if( userYear % 100 =- e) return false; 8 9. 10 else if( userYear % 4 == 0) return true; 11 12 13 14 else 15 return false; 16 } 17
A common year in the modern Gregorian Calendar consists of 365 days. In reality, Earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines the number of days in February for that year. Ex: If the input is: 1712 the output is: 1712 has 29 days in February. Ex: If the input is: 1913 the output is: 1913 has 28 days in February. Your program must define and call the following function. The function should return the number of days in February for the input year. int DaysInFeb (int userYear) 378260.2498516 qudzay? LAB LAB: Leap year - functions АCTIVITY main.c Load default template. 1 #include 2 #include 3 4 int DaysInFeb (int userYear) { if( userYear % 400 -- 0) return true; 7 else if( userYear % 100 =- e) return false; 8 9. 10 else if( userYear % 4 == 0) return true; 11 12 13 14 else 15 return false; 16 } 17
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Transcribed Image Text:A common year in the modern Gregorian Calendar consists of 365 days. In reality, Earth takes longer to rotate around the sun. To account
for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The
requirements for a given year to be a leap year are:
1) The year must be divisible by 4
2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400
Some example leap years are 1600, 1712, and 2016.
Write a program that takes in a year and determines the number of days in February for that year.
Ex: If the input is:
1712
the output is:
1712 has 29 days in February.
Ex: If the input is:
1913
the output is:
1913 has 28 days in February.
Your program must define and call the following function. The function should return the number of days in February for the input year.
int DaysInFeb (int userYear)
378260 2498516.quazay7
LAB
LAB: Leap year - functions
АCTIVITY
main.c
Load default template.
1 #include <stdio.h>
2 #include <stdbool.h>
4 int DaysInFeb (int userYear) {
if( userYear % 400 - e)
return true;
5
7
else if( userYear % 100 ==
return false;
9.
10
11
else if( userYear % 4 == e)
12
return true;
13
14
else
15
return false;
16 }
17
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