A conducting loop in the form of a circle isplaced perpendicular to a magnetic field of 0.50T. If the area of the loop increases at a rate of3.0 x 10-3 m2/s, what is the induced emf inthe loop?O A. 5.5 mVO B. 1.7 mVO C. 1.5 mVD. 0 mVO E. 4.3 mV A conducting bar moves along frictionlessconducting rails connected to a 4.00-Q resistoras shown in the figure. The length of the bar is1.60 m and a uniform magnetic field of 2.20 T isapplied perpendicular to the paper. What is theapplied force required to move the bar to theright with a constant speed of 6.00 m/s?wwwwO A. 8.60 NOB. 9.30 NO C. 12.6 NO D. 18.6 NO E. 10.6 NB-field 1 out ()Fapplied

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A conducting loop in the form of a circle is placed perpendicular to a magnetic field of 0.50 T. If the area of the loop increases at a rate of 3.0 x 10-3 m2/s, what is the induced emf in the loop? O A. 5.5 mV O B. 1.7 mV O C. 1.5 mV D. 0 mV O E. 4.3 MV

A conducting loop in the form of a circle is placed perpendicular to a magnetic field of 0.50 T. If the area of the loop increases at a rate of 3.0 x 10-3 m2/s, what is the induced emf in the loop? O A. 5.5 mV O B. 1.7 mV O C. 1.5 mV D. 0 mV O E. 4.3 MV

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter23: Faraday’s Law And Inductance

Section: Chapter Questions

Problem 27P: A coil of area 0.100 m2 is rotating at 60.0 rev/s with the axis of rotation perpendicular to a...

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Question

A conducting loop in the form of a circle is
placed perpendicular to a magnetic field of 0.50
T. If the area of the loop increases at a rate of
3.0 x 10-3 m2/s, what is the induced emf in
the loop?
O A. 5.5 mV
O B. 1.7 mV
O C. 1.5 mV
D. 0 mV
O E. 4.3 mV

A conducting bar moves along frictionless
conducting rails connected to a 4.00-Q resistor
as shown in the figure. The length of the bar is
1.60 m and a uniform magnetic field of 2.20 T is
applied perpendicular to the paper. What is the
applied force required to move the bar to the
right with a constant speed of 6.00 m/s?
wwww
O A. 8.60 N
OB. 9.30 N
O C. 12.6 N
O D. 18.6 N
O E. 10.6 N
B-field 1 out ()
Fapplied

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