A curved arrow mechanism for a Bronsted acid-base reaction is shown below. Choose the best explanation for this proposed curved arrow mechanism.

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter15: Acid–base Equilibria
Section: Chapter Questions
Problem 7P
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second arrow indicates the
electrons from the O-H bond moving to the
oxygen of the oxonium breaking the O-H bond.
C) The arrow points at the proton that is
electron deficient. This proton is bonded to an
electronegative oxygen creating a dipole where
the hydrogen has a low electron density. The
electrons follow the arrow from this proton to
the nitrogen of the diisopropylamine resulting in
the formation of a new bond. The second arrow
indicates the electrons from the O-H bond
move to the oxygen creating neutral ethanol.
D) The arrow points at the proton that is
electron deficient. This proton is bonded to an
electronegative oxygen creating a dipole where
the hydrogen has a low electron density. The
electrons follow the arrow from the base (N of
diisopropylamine) to this hydrogen atom
resulting in the formation of a new bond. The
second arrow indicates the electrons from the
O-H bond moving to the oxygen of the oxonium
breaking the O-H bond creating neutral ethanol.
3:03 PM
6/21/2023
Transcribed Image Text:Search second arrow indicates the electrons from the O-H bond moving to the oxygen of the oxonium breaking the O-H bond. C) The arrow points at the proton that is electron deficient. This proton is bonded to an electronegative oxygen creating a dipole where the hydrogen has a low electron density. The electrons follow the arrow from this proton to the nitrogen of the diisopropylamine resulting in the formation of a new bond. The second arrow indicates the electrons from the O-H bond move to the oxygen creating neutral ethanol. D) The arrow points at the proton that is electron deficient. This proton is bonded to an electronegative oxygen creating a dipole where the hydrogen has a low electron density. The electrons follow the arrow from the base (N of diisopropylamine) to this hydrogen atom resulting in the formation of a new bond. The second arrow indicates the electrons from the O-H bond moving to the oxygen of the oxonium breaking the O-H bond creating neutral ethanol. 3:03 PM 6/21/2023
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Question 10 of 21
A curved arrow mechanism for a Bronsted acid-base reaction is shown below.
Choose the best explanation for this proposed curved arrow mechanism.
H
A) The arrow points at the proton that is
electron rich. This proton is bonded to an
electronegative oxygen creating a dipole where
the hydrogen has a high electron density. The
electrons follow the arrow from the oxygen of
the oxonium to the hydrogen. In a second
arrow, this electron rich hydrogen atom bonds.
to the nitrogen of the diisopropylamine showing
the formation of a new bond.
B) The arrow points at the proton that is
electron rich. This proton is bonded to an
electronegative oxygen creating a dipole where
the hydrogen has a high electron density. The
electrons follow the arrow from the basic amine
to this hydrogen showing the formation of a
new bond. The second arrow indicates the
electrons from the O-H bond moving to the
oxygen of the oxonium breaking the O-H bond.
C) The arrow points at the proton that is
electron deficient. This proton is bonded to an
electronegative oxygen creating a dipole where
the hydrogen has a low electron density. The
electrons follow the arrow from this proton to
the nitrogen of the diisopropylamine resulting in
the formation of a new bond. The second arrow
indicates the electrons from the O-H bond.
Submit
D 3:35 PM
Transcribed Image Text:+ Question 10 of 21 A curved arrow mechanism for a Bronsted acid-base reaction is shown below. Choose the best explanation for this proposed curved arrow mechanism. H A) The arrow points at the proton that is electron rich. This proton is bonded to an electronegative oxygen creating a dipole where the hydrogen has a high electron density. The electrons follow the arrow from the oxygen of the oxonium to the hydrogen. In a second arrow, this electron rich hydrogen atom bonds. to the nitrogen of the diisopropylamine showing the formation of a new bond. B) The arrow points at the proton that is electron rich. This proton is bonded to an electronegative oxygen creating a dipole where the hydrogen has a high electron density. The electrons follow the arrow from the basic amine to this hydrogen showing the formation of a new bond. The second arrow indicates the electrons from the O-H bond moving to the oxygen of the oxonium breaking the O-H bond. C) The arrow points at the proton that is electron deficient. This proton is bonded to an electronegative oxygen creating a dipole where the hydrogen has a low electron density. The electrons follow the arrow from this proton to the nitrogen of the diisopropylamine resulting in the formation of a new bond. The second arrow indicates the electrons from the O-H bond. Submit D 3:35 PM
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