A fuel contains 45% of H₂, 40% CO, 12% CH, and 3% O₂ by volume. Determine volume of air required to burn 1 m³ of this fuel. H -45% = 0.45 m² CO -40% - 0.4m³ Ote -12 % - 0.12 m²

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Problem 13CR: What does “STP’ stand for? What conditions correspond to STP? What is the volume occupied by one...
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A fuel contains 45% of H₂, 40% CO, 12% CH, and 3% O₂ by volume.
Determine volume of air required to burn 1 m³ of this fuel.
H₂ -45% 0.45 m³
CO -40%
0.4m³
CH-12% - 0.12 m²
Transcribed Image Text:Question:- A fuel contains 45% of H₂, 40% CO, 12% CH, and 3% O₂ by volume. Determine volume of air required to burn 1 m³ of this fuel. H₂ -45% 0.45 m³ CO -40% 0.4m³ CH-12% - 0.12 m²
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