A golfer tees off from the top of a rise, giving the golf ball an initial velocity of 44 m/s at an angle of 28° above the horizontal. The ball strikes the fairway a horizontal distance of 190 m from the tee. Assume the fairway is level. (a) How high is the rise above the fairway? (b) What is the speed of the ball as it strikes the fairway?

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Motion In Two Dimensions
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A golfer tees off from the top of a rise, giving the golf ball an initial velocity of 44 m/s at an angle of 28° above the horizontal. The ball
strikes the fairway a horizontal distance of 190 m from the tee. Assume the fairway is level. (a) How high is the rise above the fairway?
(b) What is the speed of the ball as it strikes the fairway?
Transcribed Image Text:A golfer tees off from the top of a rise, giving the golf ball an initial velocity of 44 m/s at an angle of 28° above the horizontal. The ball strikes the fairway a horizontal distance of 190 m from the tee. Assume the fairway is level. (a) How high is the rise above the fairway? (b) What is the speed of the ball as it strikes the fairway?
Expert Solution
Step 1

Calculate the initial velocity of the ball along the horizontal and vertical directions, respectively.

ux=(44 m/s)cos28°=38.85 m/suy=(44 m/s)sin28°=20.657 m/s

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