A laminated wood beam consists of six 2 x 6 in planks glued together to form a section 6 in wide by 12 in deep, as shown on the right below. If the strength of the glue in shear is 120 psi, determine the maximum uniformly distributed load w that can be applied over the full length of the beam if the beam is simply supported and has a span of 15 ft, as shown on the left below. W 15 ft 6 in IN 12 in 12 in 12 in 12 in NNNNN 12 in 12 in

Elements Of Electromagnetics
7th Edition
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Author:Sadiku, Matthew N. O.
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A laminated wood beam consists of six 2 x 6 in planks glued together to form a section
6 in wide by 12 in deep, as shown on the right below. If the strength of the glue in shear
is 120 psi, determine the maximum uniformly distributed load w that can be applied
over the full length of the beam if the beam is simply supported and has a span of
15 ft, as shown on the left below.
ω
15 ft
- 6 in
[2 in
12 in
12 in
12 in
12 in
2 in
Transcribed Image Text:A laminated wood beam consists of six 2 x 6 in planks glued together to form a section 6 in wide by 12 in deep, as shown on the right below. If the strength of the glue in shear is 120 psi, determine the maximum uniformly distributed load w that can be applied over the full length of the beam if the beam is simply supported and has a span of 15 ft, as shown on the left below. ω 15 ft - 6 in [2 in 12 in 12 in 12 in 12 in 2 in
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Strength of glue in shear = 120psi

Find the maximum uniform distributed load 

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