A link is loaded as shown, it is attached with two bolts with a diameter of and its thickness is 0.1 in, if the average normal stress in the link is 20 ksi (away from the bolts) determine the applied force G, the shear stress of a bolt as well as the bearing stress in one of the bolt holes. 2 in G
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- Solve the preceding problem if F =90 mm, F = 42 kN, and t = 40°MPaThe lap joint shown is fastened by five ¾ inch-diameter rivets. The bearing stress in the plates is limited to 10 ksi and the shearing stress in the rivets is 15 ksi. Assume the applied load is equally distributed among the five rivets. The thickness of each plate is ½ in. Calculate the load P based on each stress given. Determine the maximum safe load P that can be applied. Express the loads in kips.The stress in a wire of diameter 2 mm if a load of 100 gm is applied to a wire.
- Two solid cylindrical rods (1) and (2) are joined together at flange B and loaded as shown. If F₁ = 15 kips, F₂ = 34 kips, and the normal stress in each rod must be limited to 21 ksi, determine the minimum diameter d₁ required for rod (1). F₂ (1) F₁ 1.023 in. 0.954 in. 0.682 in. 1.108 in. 0.585 in. F₂ B C d₁ -d₂06. The lap joint is connected by three 20-mm diameter rivets. Assuming that the axial load P = 50 kN is distributed among the three rivets, find a. the shear stress in each rivet; b. the bearing stress between the plate and a rivet; the maximum average tensile stress in each plate. С. Express your answer in MPa 130 mm O O O 3/4 25 mm 25 mmA solid square steel bar is fixed at one end as shown, and is loaded with a 25 kg weight. If the limiting stress of the bar is 27.24 kPa determine the cross sectional area of the steel square bar and its dimensions.
- Assume that the axial load P applied to the lap joint is distributed equally among the three 20-mm-diameter rivets. What is the maximum load P that can be applied if the allowable stresses are 40 MPa for shear in rivets, 90 MPa for bearing between a plate and a rivet, and 120 MPa for tension in the plates?A knuckle joint is used to connect two circular rods. The tensile force applied is 50 kN. The tensile stress in the rod and the shear stress in the pin are 25.46 MPa and 35.37 MPa, respectively. Determine the required diameter of the rod and the pin in mm.3. The composite bar consists of a 20-mm diameter steel segment AB and 50-mm diameter brass end segments DA and CB. Find the stress on each segment due to the applied loads. E of steel is 200 GPa and E of brass is 101 GPa. 250mm 250mm 250mm 50mm 20mm 50mm 75KN 100KN brass steel brass D B C 75KN 100KN
- Q3/ Two plates are riveted together have a width of 130 mm , thickness of 25 mm and the diameter of the rivet bolt is 10 mm. When it's subjected to a load of 150 KN as shown in fig.2, determine: 1- tensile stress 2-shearing stress 3-bearing stress. 10mm= 130 mm 25 mm 25 mm Fig.23- The modulus of elasticity, and the modulus of resilience. 4- The final or fracture strain of a steel specimen, if you know that the final length of specimen after testing is 58.5mm. 5- The true stress and strain for ultimate point. Q3: The yoke-and-rod connection is subjected to a tensile force of 15 kN. Determine the average normal stress in each rod and the average shear stress in the pin A between the members. Finally, find the shear strain in pin A. Take G steel= 75GPA 40 mm 15 kN. 30 mm 30 mm 15 kN 04: In figure as shown below, assume that a 35mm diameter rivet joint the plates which are each 150mm wide. (a) if the allowable stresses 200 MPa for bearing in the plate material and 120 MPa for shearing of the rivet, determine the minimum thickness of each plate. (b)Under the conditions specified in part (a) what is the largest average stress in the plate. 35mmThe T-bracket is formed by welding together two cylindrical rods AB and CD. If the allowable shear stress is 80 MPa, what is the smallest allowable diameter of rod AB? Neglect the stress caused by the transverse shear force