A mass of TAG (2.151 g) was weighed out accurately. It was then subject to reflux with 100.0 mL of 0.250 M potassium hydroxide. The unreacted potassium hydroxide was titrated with 0.250 M hydrochloric acid using phenolphthalein as indicator. 19.6 mL of the HCI solution were required. Calculate the saponification value of the TAG. Show your working. NB: The Molecular weight of KOH is 56.1056 g/mol.

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
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Chapter16: Applications Of Neutralization Titrations
Section: Chapter Questions
Problem 16.20QAP
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A mass of TAG (2.151 g) was weighed out accurately. It was then subject to reflux with 100.0 mL of 0.250 M potassium hydroxide. The unreacted potassium hydroxide was titrated with
0.250 M hydrochloric acid using phenolphthalein as indicator. 19.6 mL of the HCI solution were required. Calculate the saponification value of the TAG. Show your working.
NB: The Molecular weight of KOH is 56.1056 g/mol.
Transcribed Image Text:Chemistry A mass of TAG (2.151 g) was weighed out accurately. It was then subject to reflux with 100.0 mL of 0.250 M potassium hydroxide. The unreacted potassium hydroxide was titrated with 0.250 M hydrochloric acid using phenolphthalein as indicator. 19.6 mL of the HCI solution were required. Calculate the saponification value of the TAG. Show your working. NB: The Molecular weight of KOH is 56.1056 g/mol.
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