A mercury atom emits light at many wavelengths, two of which are at (1) 404.7 nm and (2) 435.8 nm . Both of these transitions are to the same final state. Determine the energy of each emitted wavelength (in J). A) E1 = 7.908 x 10-19 J and E2 = 6.558 x10-19 J B E1 = 4.628 x 10-19 J and E2 = 4.968 x10-19 J c) E1 = 5.908 x 10-19 J and E2 = 5.558 x10-19 J D E1 = 4.908 x 10-19 J and E2 = 4.558 x10-19 J

Modern Physics
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ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
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Chapter4: The Particle Nature Of Matter
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A mercury atom emits light at many wavelengths, two of which are at (1) 404.7 nm and (2) 435.8 nm . Both of these transitions are
to the same final state. Determine the energy of each emitted wavelength (in J).
A
E1 = 7.908 x 10-19 J and E2 = 6.558 x10-19 J
E1 = 4.628 x 10-19 J and E2 = 4.968 x10-19 J
E1 = 5.908 x 10-19 J and E2 = 5.558 x10-19J
E1 = 4.908 x 10-19 J and E2 = 4.558 x10-19 J
Transcribed Image Text:A mercury atom emits light at many wavelengths, two of which are at (1) 404.7 nm and (2) 435.8 nm . Both of these transitions are to the same final state. Determine the energy of each emitted wavelength (in J). A E1 = 7.908 x 10-19 J and E2 = 6.558 x10-19 J E1 = 4.628 x 10-19 J and E2 = 4.968 x10-19 J E1 = 5.908 x 10-19 J and E2 = 5.558 x10-19J E1 = 4.908 x 10-19 J and E2 = 4.558 x10-19 J
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