A nectarine is a peach without the fuzz. The difference is controlled by a single gene that is found in two alleles, D and d. At themolecular level, do you think that the nectarine is homozygous fora recessive allele or that the peach is homozygous for the recessiveallele? Explain your reasoning
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A nectarine is a peach without the fuzz. The difference is controlled by a single gene that is found in two alleles, D and d. At the
molecular level, do you think that the nectarine is homozygous for
a recessive allele or that the peach is homozygous for the recessive
allele? Explain your reasoning
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- A nectarine is a peach without the fuzz. The difference is controlledby a single gene that is found in two alleles, D and d. At themolecular level, does it make more sense to you that the nectarineis homozygous for the recessive allele or that the peach is homozygousfor the recessive allele? Explain your reasoning.n pea plants, the appearance of flowers along the main stem is a dominant phenotype called axial and is controlled by the T allele. The recessive phenotype, produced by the E t allele, has flowers only at the end of the stem and is called terminal. Seedpod form iS determined by a second gene. The dominant phenotype inflated is controlled by allele C, and a recessive constricted form, produced by allele c. A pure breeding axial, constricted plant is crossed to one that is pure-breeding terminal, inflated. A. The F1 progeny of this cross are allowed to self-fertilize. What is the expected distribution of phenotypic classes among the F2 progeny? -> TTcc t난 CC x Et 1:2:1Gene S controls the sharpness of spines in a type of cactus. Cactuses with the dominant allele have sharp spines, whereas homozygous recessive cactuses have dull spines. At the same time, a second gene, N, determines whether or not cactuses have long or short spines. Homozygous recessive cactuses have short spines. A cross between a homozygous sharp-long cactus and a dull short-spined cactus would produce what percentage of sharp-long cacti?
- Gene S controls the sharpness of spines in a type of cactus. Cactuses with the dominant allele have sharp spines, whereas homozygous recessive cactuses have dull spines. At the same time, a second gene, N, determines whether or not cactuses have long or short spines. Homozygous recessive cactuses have short spines. A cross between a homozygous sharp-long cactus and a dull short-spined cactus would produce what percentage of sharp-long cacti? Show your Punnett square please.n an example of recessive epistasis the deposition of pigment into hair follicles of the Labrador Retriever is governed by a dominant gene (C) and lack of deposition by its recessive allele (c). Lack of pigment deposition produces a yellow coat color. The color of pigment is governed by an independently assorting hypostatic gene, the dominant allele (B) produces black pigment and its recessive allele (b) produces brown. What coat color ratio is expected from the cross of a brown dog (bbCc) to a black dog (BbCc)? 1/2 brown, 1/2 black 1/4 black, 1/4 brown, 1/2 yellow 1/2 black, 1/4 brown, 1/4 yellow 3/8 black, 1/8 brown, 1/2 yellow 3/8 black, 3/8 brown, 1/4 yellowSuppose there are four newly discoverecd genes, each with two allcles, in humans that all follow a simple Mendelian inheritance pattern. Alleles are noted by a + or- for dominant and recessive, respectively. The genes and their phenotypes are listed in the table. Gene Recessive Phenotype Dominant Phenotype Wiz have the ability to cast spells cannot cast spells Serp can communicate with snakes cannot talk to snakes have the ability to travel through time experience normal time Time Drgn have the ability to hatch dormant dragon eggs cannot hatch dragon eggs What is the probability of two completely heterozygous parents having a child with a Wiz Wiz Serp Serp genotype or a child with a Wiz Wiz Serp Serp genotype? Enter your answer as a decimal. genotype probability 口 17°C ) a 202 acer HUAWEI P30 lite TRIPLE CAMERA
- What explains how the parents in a family both have the same eye color, but some of their children have a different eye color? Assume for this example that eye color is determined by a single gene. ● One parent is homozygous dominant, and the other homozygous recessive for a gene that controls eye color allowing some of the children to express a different trait. O The parents are both heterozygous for a gene that controls eye color allowing some of the children to get two recessive alleles. O The parents are both homozygous dominant for a gene that controls eye color allowing some of the children to get two recessive alleles. O One parent is homozygous dominant, and the other heterozygous for a gene that controls eye color allowing some of the children to express a different trait.In cats, the allele (B) produces black color but (b) producesyellow color. These alleles are co‐dominant to each other. Aheterozygote produces a tortoise‐shell color. The alleles (B)and (b) are sex‐linked as well. Cross a tortoise‐shell femalewith a yellow male. What percent of their offspring will be yellow? What percent of their offspring will be black? What percent of their offspring will be tortoise shell?White fruit color in summer squash is dependent on a dominant gene (W) and colored fruit to the recessive gene (w). In the presence of ww a dominant gene D produces yellow color, but when D is not present, the color is green. Upload your solution in the google classroom. Give the: F1_phenotypes_expected_from_crossing_white_fruited_WWDD_with_green_fruited_wwdd_plant F2_phenotypes_expected_from_crossing_the_F1 F2_phenotypic_ratio_expected_from_crossing_the_F1 F2_genotypic_ratio_expected_from_crossing_the_F1 Type_of_epistatis Write all phenotypes in CAPITAL letters SEPARATED BY COMMA. Write all ratio in numerical values without spaces
- The comb shape of chickens is an example of an interesting inheritance pattern. Two genes, each with a dominant and recessive allele, determine comb phenotypes as follows: Comb Shape Description Genotype Single Comb homozygous recessive for both r and p rrpp Walnut comb both dominant alleles are present; R and P alleles are present R_P_ Pea comb the dominant allele P is present and the dominant allele R is absent rrP_ Rose comb the dominant allele R is present and the dominant allele P is absent R_pp Which of the following represents the correct phenotypes of the F2 offspring? Select one: a. Phenotype Single Walnut Pea Rose 9/16 3/16 3/16 1/16 b. Phenotype Single Walnut Pea Rose 3/16 1/16 9/16 3/16 c. Phenotype Single Walnut Pea Rose 1/16 9/16 3/16 3/16 d. Phenotype Single Walnut Pea Rose 3/16 9/16 1/16 3/16The comb shape of chickens is an example of an interesting inheritance pattern. Two genes, each with a dominant and recessive allele, determine comb phenotypes as follows: Comb Shape Description Genotype Single Comb homozygous recessive for both r and p rrpp Walnut comb both dominant alleles are present; R and P alleles are present R_P_ Pea comb the dominant allele P is present and the dominant allele R is absent rrP_ Rose comb the dominant allele R is present and the dominant allele P is absent R_pp If the P1 generation is a rose comb (RRpp) crossed with a pea comb (rrPP), which of the following represents the correct genotype and phenotype of the F1 offspring? Select one: a. Genotype Phenotype RRPP Single comb b. Genotype Phenotype RrPp walnut comb c. Genotype Phenotype RrPp pea comb d. Genotype Phenotype RRPP walnut combTwo genes, U and H, affect wing development in a species of flying pigs, where some pigs have wings and some do not. Pigs with wings must have at least one copy of allele U¹. Among pigs with wings, allele H4 codes for grey feathers and is dominant over allele H5, which codes for white feathers. Which of the following best describes this scenario? O Duplicate Recessive Epistasis Recessive epistasis of H over U Dominant epistasis of H over U Recessive epistasis of U over H Duplicate Dominant Epistasis O Dominant epistasis of U over H