A Neilson Company report states that the mean number of TV sets in the U.S. household is 2.24. Assume the standard deviation of the population is 1.2. A sample of 100 households is taken Let x¯ be the sample mean number of TV sets in households. a) x¯ ~ Normal (=      ["", "", "", ""]    ,    =       ["", "", "", ""]  ) b) The probability that the sample mean number of TV sets in the 100 households is greater than 2 is       ["", "", "", ""]  c) The 30th percentile of the sample

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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A Neilson Company report states that the mean number of TV sets in the U.S. household is 2.24. Assume the standard deviation of the population is 1.2. A sample of 100 households is taken

Let x¯ be the sample mean number of TV sets in households.

a) x¯ ~ Normal (=      ["", "", "", ""]    ,    =       ["", "", "", ""]  )

b) The probability that the sample mean number of TV sets in the 100 households is greater than 2 is       ["", "", "", ""] 

c) The 30th percentile of the sample mean of TV sets is       ["", "", "", ""] 

 
 
 

The National Health and Nutrition Examination Survey reported in the recent year, the mean cholesterol level for U.S. adults was 202 with standard deviation of 41 (unit: mg/dl)

A simple random sample of 110 adults are chosen.

Let x¯ be the sample mean cholesterol with     

a) The probability that the sample mean cholesterol level of the sample of 110 is greater than 210 is P(x¯>210) =      ["", "", "", ""]   

b) What is the probability that the sample mean is between 190 and 200: P(190<x¯<200) =      ["", "", "", ""] 

 

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