A nonconducting slab with volume charge density p has a finite thickness between z = - d and z = +d and is infinite in the plane perpendicular to the z-axis. Enter the correct expression of the electric field inside and outside the slab. Express your answers in terms of p, d, z, and €0.
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- a) Find the surface charge density σ2 of the cylindrical shell of radius R2. (Note the unit in the input box and the sign of charges.) Surface charge density σ2Give your answer up to at least three significance digits. b) Find an expression of electric field at rmm from the center where R1<r<R2. Assume the cylinder has a length L and L is very long so that electric field is uniform. Consider that the insulating material between the cylinders is air. (Hint : use Gauss's law and cylindrical Gaussian surface with radius r.) Magnitude of the electric field at r=0.76mm Give your answer up to at least three significance digits. c) Calculate absolute value of the potential difference between the wire and the cylinder. Absolute value of the potential difference Give your answer up to at least three significance digits. d) Calculate the capacitance C for this cylindrical system. Assume that the length of the cylinder is L=17cm. Capacitance C for this cylindrical system Give your…Charge is distributed throughout a spherical volume of radius R with a density p = ar², where a is a constant (of unit C/m³, in case it matters). Determine the electric field due to the charge at points both inside and outside the sphere, following the next few steps outlined. Hint a. Determine the total amount of charge in the sphere. Hint for finding total charge Qencl = (Answer in terms of given quantities, a, R, and physical constants ke and/or Eg. Use underscore ("_") for subscripts, and spell out Greek letters.) b. What is the electric field outside the sphere? E(r> R) = c. What is the electric field inside the sphere? Hint for E within sphere #3 Question Help: Message instructor E(r < R) = Submit Question E с $ 4 R G Search or type URL % 5 T ^ MacBook Pro 6 Y & 7 U * 8 9 0 0A solid insulating sphere of radius R has a volume charge density p given by p= pexp(-r/a"), where po.a >0 are both constants and r is the distance from the center of the insulator. Which of the following gives the correct expression for the electric fiekd magnitude at a distancer< R inside the insulator? A. E- exp В. Е exp fo 3 c. E = - (-)} D. E = - e(-)} exp E. E= 1-exp
- 1 ! 7 A skát с A spherically symmetric charge distribution produces the electric field E=( 5400 r²) N/C, where r is in m. Z mylabmastering.pearson.com/?courseld=12649908&key=55673220682936520262024#/ 2 pos W S X 3 20 F3 E D $ 4 C 888 R F What is the electric field strength at r= 16.0 cm ? Express your answer in newtons per coulomb. VG ΑΣΦ 4 Submit Part B Submit Part C What is the electric flux through a 32.0-cm-diameter spherical surface that is concentric with the charge distribution? Express your answer in newton meters squared per coulomb. ΕΠΙ ΑΣΦ % [VG| ΑΣΦ 5 Request Answer V FO Request Answer T How much charge is inside this 32.0-cm-diameter spherical surface? Express your answer in coulombs. G 4 a ^ 6 C 244 MacBook Air Y B SMC & ? 7 H ? N/C 80 F7 N-m²/C U C N H 8 - DII FS 1 ( 9 M DD K chegg.com X C ☆ O O MOSISO O 4 PA closed surface with dimensions a = b 0.272 m and c = the figure. The electric field throughout the region is nonuniform and defined by E (a+ Br)î where r is in meters, a = 3 N/C, and 3 = 5 N/(C -m²). 0.4896 m is located as in E What is the magnitude of the net charge enclosed by the surface? Answer in units of C. A. to sh What is the sign of the charge enclosed in the surface? R 1. Cannot be determined 2. Negative 3. PositiveThe figure below is a cross section of three non . plates conductor of infinite width, where the charge is evenly distributed. 01 02 (1/2) L . 2L R 03 The charge density on the surface of each plate is 1 = - 3µC/m2, 2 =+ 5µC/m2 , 3 = - 5µC/m2 , and L = 2 cm. In vector notation, what is the field net electricity at points P and R?
- A non-uniformly charged insulating sphere has a volume charge density p that is expressed as p= Br where B is a constant, and r is the radius from the center of the sphere. If the, the total charge of the sphere is Q and its maximum radius is R. What is the value for B? Sol. By definition, the volume charge density is expressed infinitesimally as p= where in is the infinitesimal charge and is the infinitesimal volume. so, we have P = dq/ = B so we can write this as dq = B dV But, dV = dr By substitution, we get the following dq = 4B dr Using Integration operation and evaluating its limits, the equation, leads to Q = Rearranging, we get B = 4)A non-uniformly charged insulating sphere has a volume charge density p that is expressed as p= Br where B is a constant, and r is the radius from the center of the sphere. If the, the total charge of the sphere is Q and its maximum radius is R. What is the value for B? Sol. By definition, the volume charge density is expressed infinitesimally as p= where in is the infinitesimal charge and is the infinitesimal volume. so, we have p = dq/ So we can write this as dq = B dV %3D But, dV = drA non-uniformly charged insulating sphere has a volume charge density p that is expressed as p= Br where B is a constant, and r is the radius from the center of the sphere. If the, the total charge of the sphere is Q and its maximum radius is R. What is the value for B? Sol. By definition, the volume charge density is expressed infinitesimally as p= where in is the infinitesimal charge and is the infinitesimal volume. So, we haye p = dq/ So we can write this as dq = B dV But, dV = dr By substitution, we get the following dq = 4BT dr Using Integration operation and evaluating its limits, the equation, leads to Q = BT Rearranging, we get B = /( T
- The surface charge density on a long straight metallic pipe is a. What is the electric field outside and inside the pipe? Assume the pipe has a diameter of 2a. (Enter the magnitudes. Use any variable or symbol stated above along with the following as necessary: r for the radial distance from the axis of the pipe and cq.) outside the pipe Inside the pipe 00 E(r) = E(r) 0.The electric field at a distance of 0.157 m from the surface of a solid insulating sphere with radius 0.361 m is 1730 N/C. Part A Assuming the sphere's charge is uniformly distributed, what is the charge density inside it? Part B Calculate the electric field inside the sphere at a distance of 0.214 mfrom the center.Part A In terms of the total charge Q, estimate the electric field on the axis at point 0.02R from the center of the ring. Express your answer in terms of some or all of the variables Q, Ro, and the appropriate constants. E0.02 Ro Submit Part B E75 Ro = = VE ΑΣΦ In terms of the total charge Q, estimate the electric field on the axis at point 75Ro from the center of the ring. Submit Request Answer Express your answer in terms of some or all of the variables Q, Ro, and the appropriate constants. VE ΑΣΦ ? Request Answer X ?