A particle has a velocity of (t) = 5ti+1.1t²j-2t³k S Assume all quantities are correct to 2 significant figures. (a) Calculate the acceleration as a function of time? (Note: write your coefficients in terms of the variable 't'.) Enter to 2 significant figures a(t) = + (b) What is the acceleration vector at t = 1.7 s in the unit vector notation? Enter to 2 significant figures a(1.7 s) = |a (1.7 s) |=| i+ + (c) What is the magnitude of the acceleration vector at t = 1.7 s? Enter to 2 significant figures m/s² m E% m

A particle has a velocity of (t) = 5ti+1.1t²j-2t³k S Assume all quantities are correct to 2 significant figures. (a) Calculate the acceleration as a function of time? (Note: write your coefficients in terms of the variable 't'.) Enter to 2 significant figures a(t) = + (b) What is the acceleration vector at t = 1.7 s in the unit vector notation? Enter to 2 significant figures a(1.7 s) = |a (1.7 s) |=| i+ + (c) What is the magnitude of the acceleration vector at t = 1.7 s? Enter to 2 significant figures m/s² m E% m

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 2P

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1つ7 3. An object undergoes motion in 2 dimensions under a constant acceleration of "-2.50 m/s at an angle of 50.0° with respect to the + x direction. It also has an initial velocity of vi = 7.00 m/s at an angle of 10,0° The object begins at the coordinates (0, 0). a) What are the coordinates of the object at t = 7.00 s? Want Cx, y) at t =?4 4tzテメ0チ=XT vse this Con Vxi = \V;l cos v +ハ Ay=lalsin Ga b) What is its total velocity vector of the object as a magnitude and direction at t = 7.00 s? a) Ov= Ton
A particle moves along two dimensions based on the following position vector r= [2.0 m + (3.00 m/s)f ]i + [(3.0 m)t - (2.00 m/s2)rlj a. Find the distance it covered in the first minute. b. Find the general expression of the instantaneous acceleration of the particle.
3. A jet plane is flying at a constant altitude. At time it has components of velocity. At time tį = 0 it has components of velocity vz = 90", v, = 110". At time t, = 30.0 sec the components are vz = -170", v, = 40". a) Sketch the velocity vectors at t, and How do these two vectors differ? For this time interval calculate (b) the t2. components of the average acceleration, and (c) the magnitude and direction of the average acceleration.
I took 2.28km and converted it to 2280 meters then divided by 3200 and ended up with .71m/s but it keeps saying that its incorrect. Im not sure where I keep messing up. John walks 1.80 kmkm north, then turns right and walks 1.40 kmkm east. His speed is 1.60 m/sm/sduring the entire stroll. What is the magnitude of his displacement, from beginning to end? (2.28) If Jane starts at the same time and place as John, but walks in a straight line to the endpoint of John's stroll, at what speed should she walk if she wants to arrive at the endpoint just when John does?
3. The vector position of a particle varies in time according to the expression r = (3.00i – 6.00ť²j) m. (a) Find expres sions for the velocity and acceleration as functions of time. (b) Determine the particle's position and velocity at t = 1.00 s.
1110. In Fig. P-1109, a ball thrown down the incline strikes it at a distance s 254.5 It. If the ball rises to a maximum height h 64.4 ft above the point of release, compute its initial velocity vo and inclination 6. Ans. v. = 80.5 ft per see; 0= 53.1° FIG. P-1109 and P-1110.
A body moves in space , the location vector r 2 = 2t i +tj +2 k m, How much the velocity of it at 2 second V = m/sec (2 aic aïcw ya ps ?) ثانيه Select one: a. 10.05 mls b. 8.06 m/s c. 9.03 m/s d. 7.02 m/s
My question isn't how to solve the problem exactly. In fact, it's already been solved on this website. My question is about the acceleration. When I solve this problem myself, first I calculate the velocity by dividing 100m by 53s. I get 1.89m/s. Then I use that to find the acceleration using the equation vf = vi + at. That's 1.89/53 = 0.036m/s^2. That's not correct. The correct way to find the acceleration is to us the equation d = 1/2 at^2 and solve that way without taking the intermediate step of finding the velocity. Doing it that way, the acceleration is 0.0712m/s^2. My question is why you get a different result doing it the first way than you get doing it the second way.
ar.C PH 8 7.2 Projectile Motion | School: i the ercher launches the ams + IA T The Tragic Events.. Submit Assignment G Allan poe poems th.. Edgar Allan Poe Qu. A Edgar Allan Poe, P.. G Graphic novel of ed. Motion - 15056140 * O ensions Help Last edit was yesterday at 8:12 AM BIUA CD 田回▼ - 1三 m ▼=▼三EX Arial 21 I 1 I 2 3 4 5 I I 6 1. If the archer launches the arrow with a speed of 10 m/s while kneeling 8 m from the target, what launch angle is required for the arrow to hit the target? (Adjust the Position slider to Kneeling, the Distance to Target slider to 8 m, and the Launch Speed slider to 10 m/s. Then, adjust the Launch Angle slider until the arrow hits the target after pressing play.) Support I Schoology Blog | PRIVACY POLICY I Terms of Use DELL
An object is moving with an initial velocity of 5.8 i m/s and a final velocity 13.8 i m/s. The time taken for acceleration is 2.2 seconds. Calculate the acceleration in m/s2 to 2 sf. In your answer, you do not enter the i unit vector, but you do need to enter negative signs, if appropriate. e.g. if your answer is a = -5.4 i m/s,2 you would enter -5.4
The acceleration of a particle is given by a = 2t-20, where a is in meters per second squared and t is in seconds. Determine the velocity and displacement as functions of time. The initial displacement at t = 0 is so = -5 m, and the initial velocity is vo = 6 m/s. Once you have determined the functions of time, answer the questions. Questions: When t = 5.1 s, S= V = a = Mi MI i m m/s m/s²
In 1991, four English teenagers built an electric car that has a velocity of 3 m/s [N 30⁰ E]. Suppose it takes 8.0 s for this car to accelerate to the new velocity of 18.0 m/s [W 30⁰ S]. What is the magnitude of the car’s acceleration?