A particle starts from zo = 22 m at to=0 and moves with thevelocity graph shown in (Eigure 1).You may want to review (Pages 41-43).Figurev, (m/s)12Z1238401 of 1r(s)SubmitValuePart CUnitsPrevious Answers Request AnswerX Incorrect; Try Again; 3 attempts remainingValueWhat is the object's position at t=48?Express your answer to two significant figures and include the appropriate units.?UnitsSubmit Previous Answers Request Answer?X Incorrect; Try Again; 3 attempts remaining

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A particle starts from ze=22 m at fo=0 and moves with the velocity graph shown in (Figure 1). You may want to review (Pages 41-43). Figure v, (m/s) 12 8 4 0 (0) 1 of 1 Submit Value Part C Units Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining Submit What is the object's position at t-4s? Express your answer to two significant figures and include the appropriate units. Value ? Units Previous Answers Request Answer ? X Incorrect; Try Again; 3 attempts remaining

A particle starts from ze=22 m at fo=0 and moves with the velocity graph shown in (Figure 1). You may want to review (Pages 41-43). Figure v, (m/s) 12 8 4 0 (0) 1 of 1 Submit Value Part C Units Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining Submit What is the object's position at t-4s? Express your answer to two significant figures and include the appropriate units. Value ? Units Previous Answers Request Answer ? X Incorrect; Try Again; 3 attempts remaining

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Vectors

Section: Chapter Questions

Problem 3.62AP: After a ball rolls off the edge of a horizontal table at time t = 0, its velocity as a function of...

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After a ball rolls off the edge of a horizontal table at time t = 0, its velocity as a function of time is given by v=1.2i9.8tj where v is in meters per second and t is in seconds. The balls displacement away from the edge of the table, during the time interval of 0.380 s for which the ball is in flight, is given by r=00.3803vdt To perform the integral, you can use the calculus theorem [A+Bf(x)]dx=Adx+Bf(x)dx You can think of the units and unit vectors as constants, represented by A and B. Perform the integration to calculate the displacement of the ball from the edge of the table at 0.380 s.
In SI units, speeds are measured in meters per second (m/s). But, depending on where you live, you’re probably mole comfortable of thinking of speeds in terms of either kilometers per hour (km/h) or miles per hour (mi/h). In this problem, you will see that 1 m/s is roughly 4 km/h or 2 mi/h, which is handy to use when developing your physical Intuition. More precisely, show that (a) 1.0m/s=3.6km/h and 1.0m/s=2.2mi/h .
Hi expert. I requested to u solve handwriting with equation proof just use personal experience Solutions. No need generalized ok. Suggest to Physics expert
Quadratic Equation: x = -6±yb²–4ac 2a AT = i; – ão Vave., drot. At dave.,e Save. || At At Vx = V0x + agt Ax Vont + at? = vox + 2a,Ax Ax (vor + Va)t '0x 1) Wile E. Coyote happens to be chasing after the Roadrunner, who is traveling in the +x-direction with a constant velocity of 8.72 m/s. Wile E. Coyote has a velocity of +3.28 m/s and a constant acceleration of +2.30 m/s? at the moment it is 10.0 m behind the Roadrunner. Take the initial position of the Roadrunner to be the origin (x = 0). a) time. Hint: Your answer should look like xR = fR(t). Express the final position of the Roadrunner (with respect to the origin) as a function of b) time. Hint: Again, your answer should look like xc = Express the final position of Wile E. Coyote (with respect to the origin) as a function of fc(t). c) use the quadratic formula here, you should get two times. Consider which one, if both, of these times makes sense in the context of this problem. How much time elapses before Wile E. Coyote catches the…
Can you help me, i need a shortcut on how to know when should i use cosine or sine.here's the problem and the solution One morning, Connie walks from her house to go to a store that is 500 ft, S 40o W from her house. She starts walking 120 ft, SW; then continues walking 100 ft, 10o S of E; then sees a friend who is 700 ft, 30o N of E from where she is. What is her friend’s location, (magnitude and direction) relative to her house? (Ans. 667.54 ft, 21.79o N of E) From her friend’s location, how far and in what direction should Connie walk to finally get to the store? (Ans. 1133.08 ft, 33.83o S of W)
(the complete question is in the picture) Which of the following quantities is a scalar? A. A Xiao Lantern floating straightup in the air at 0.5 [m/s].B. Mona sprinting forward at a rateof 9 [m/s] using Illusory Torrent.C. Defeating a Geo Hypostasis in30 [s].D. A Frostarm Lawachurl sprinting5 [m] to his right to charge at you.
b): The patcutal 0.21 partile a abag the X-aris is Ulx)=822x" is Where Joules meters.2Iher is Dill be and the at Xelom, in in That acelention,
INDIO/a/MzQ1MicSMDYzOTQ2/details D.) The pauT taken irom TIILUNG he Dail unur he Tmaximum nieignt is just symmetrical with the path taken from the maximum height to the ground. Hence, we can get the range by doubling the x displacement when the ball is at its maximum y value. We will use formula 4 1 x = Vixt +5a;t x = (5 cos 53.1) (0.41) +(0)(0.41)² x = 1.23 m Range = 2x = 2 (1.23) = 2.46 m Start answering here: 1. A ball is thrown horizontally from a building 75.0 m high with a speed of 25.0 m/s. Fin the (a) vertical and horizontal components of the ball's initial velocity, (b) time of flight, and (c) velocity when the ball will strike the ground. 2. A golf player hits a ball that leaves its initial location at speed of 40.0 m/s at an angle of 38°. Find the (a) time the ball reaches the highest point of its flight, and its height h at this time, and (b) horizontal distance from the starting point to where the ball hits the ground. DO THIS!
a. Use the formula for general solution to solve the following equation b. Check for your answer. Show all the necessary steps. Dy/dt - 7y = 21
Ex. 4) Solve the equation d ih dt \b(t) а(t) b(t) wo Wi cos wt W1 coS wt -wo
Alishba wakes up late and runs to school, covering a distance of 2.55 km in a direction of [N200 E] as measured from her home. She then realizes that her friend Lydia has her homework and races over to his house 0.5 km away [W] from the school. The two friends then decide it’s not worth going to class late so they go off to the mall that is 2.8 km [W500 S]. a) What is Alishba’s total displacement? b) If the total time taken by Alishba to run to school then over to the friend’s house was 25 minutes, what was her average velocity?
I'm having a hard time figuring out which equation I need to be using to plug in the data into the table. Help!