I need this ASAP, please. A popular blog reports that 45% of college students log in to Instagram on a daily basis. The Dean ofStudents at a certain university thinks that the proportion may be different at her university. She polls asimple random sample of 203 students, and 106 of them report that they log in to Instagram daily. Can youconclude that the proportion of students who log in to Instagram daily differs from 45%? Use the a = 0.06level.a. State the null and alternative hypotheses.Ho: ? ✓? ✓Select an answer ✓H₁: ? ✓ ? ✓b. Find the critical value and sketch the rejection region.Sketch of Rejection Region:AAA+3 -3 -2-1 0-3Select an answer ✓+ + +-2 -1 0 1 2Critical value(s):c. Find the test statistic.d. Find the p-value.2 3e. Decide: Select an answer Ho-3 -2(If there are two critical values, list both values separated by a comma)+-10+23of. Conclusion: At a = 0.06 significance level, there Select an answer enough evidence to concludethat the proportion of students who log in to Instagram daily differs from 45%.

Given p=45%, n=203, X=106 , level of significance ɑ=0.06 Note: According to Bartleby guidelines…

A popular blog reports that 45% of college students log in to Instagram on a daily basis. The Dean of Students at a certain university thinks that the proportion may be different at her university. She polls a simple random sample of 203 students, and 106 of them report that they log in to Instagram daily. Can you conclude that the proportion of students who log in to Instagram daily differs from 45% ? Use the α = 0.06 level. a. State the null and alternative hypotheses. Ho : ? - ? v Select an answer V Hi: ? v ? V Select an answer b. Find the critical value and sketch the rejection region. Sketch of Rejection Region: -3 ਇਸ ਗਲ -2 -1 0 1 2 3 -3 -2 -1 0 Critical value(s): c. Find the test statistic. 2 3 -3 -2 -1 0 1 (If there are two critical values, list both values separated by a comma) 2 3