A power cycle operating at steady state receives energy by heat transfer at a rate QH at TH = 1800 K and rejects energy by heat transfer to a cold reservoir %3D at a rate Qc at Tc = 600 K. For each of the following cases, determine whethe the cycle operates reversibly, operates irreversibly, or is impossible.
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- A power cycle operating at steady state receives energy by heat transfer at a rate QH at TH = 1800 K and rejects energy by heat transfer to a cold reservoir at a rate Qc at Tc = 600 K. For each of the following cases, determine whether the cycle operates reversibly, operates irreversibly, or is impossible. (a) Qu (300) kW, Oc = (100) kW (b) QH (500)kW, Wcycle = (150)kW, Oc = (200)kW (c) Wcycle (450)kW, Oc = (150)kW (d) QH = (500)kW, Oc = (100)kWA reversible heat pump cycle operates at steady state between hot and cold reservoirs at TH = 30°C and Tc 10°C, respectively. The rate of heat transfer at the high temperature is 10 kW. a. Determine the net power input, in kW. b. Determine the heat transfer rate from the cold reservoir at Tc, in kW. c. Determine the coefficient of performance of the cycle.A power cycle operating between two reservoirs receives energy QH by heat transfer from a hot reservoir at TH = 2000 K and rejects energy Qc by heat transfer to a cold reservoir at Tc= 400 K. For each of the following cases determine whether the cycle operates reversibly, irreversibly, or does not verify the second law of thermodynamics (make all necessary calculation for each case). a) QH= 1200 kJ and Wcycle = 1020 kJ b) QH= 1200 kJ and Qc = 240 kJ c) Wcycle = 1020 kJ and Qc = 600 kJ d) n =40%
- A power cycle operating between two reservoirs receives energy Qu by heat transfer from a hot reservoir at TH = 2000 K and rejects energy Qc by heat transfer to a cold reservoir at Tc = 400 K. For the cases below you will be asked to determine the cycle n and whether the cycle operates Reversibly, Irreversibility, or is Impossible. Сycle Сycle Сycle Assume: п — пСarnot n пСarnot 1. The maximum thermal efficiency nCarnot for the cycle is equal to а. 0.2 b. 0.8 с. 1.0 d. none of the above. 2. If QH = 1100 kJ and the Weycle = 900 kJ then the cycle is Reversible b. Irreversible c. Impossible а. d. none of the above. 3. If QH = 1000 kJ and Qc = 200 kJ then the cycle is a. Reversible b. Irreversible c. Impossible d. none of the above. 4. If Wq a. Reversible b. Irreversible c. Impossible d. none of the above. суcle 1400 kJ and Qc= 600 kJ then the cycle is 5. If n = 50% then the cycle is a. Reversible b. Irreversible c. Impossible d. none of the above.Q3/ A heat pump cycle operating between two reservoirs receives energy Q2 from a cold reservoir at T2 = 250K and rejects energy Qı to a hot reservoir at T1 = 300K. For each of the following cases determine whether the cycle operates reversibly, irreversibly or is impossible. (a) Q2 =300KJ , W = 400 KJ (b) Q2 = 2000KJ , Q1 = 2200KJ (c) Q1 = 3000KJ , W= 500KJ (d) W = 400 KJ , COP =6 %3DA heat engine An engine that converts power from heat operating at a steady-state receives energy by heat transfer at a rate of Qu at TH = 1200 K and rejects energy by heat transfer to a cold reservoir at a rate Qc at Tc= 360 K. (i) Calculate the Carnot cycle efficiency (ii) For each of the following cases, analyze and determine whether the cycle operates reversibly, operates irreversibly, or is impossible. (a) QH = 720 kW, Qc = 144 kW (b) QH = 720 kVW, Wcycle = 360 kW, Qc = 288 kW (c) Wcycle = 714 kW, Qc = 306 kW (d) QH = 920 kW, Qc = 368 kW
- A power cycle operating at steady state receives energy by heat transfer at a rate Q at TH = 1800 Kand rejects energy by heat transfer to a cold reservoir at a rate Oc at Tc = 600K. For each of the following cases, determine whether the cycle operates reversibly, operates irreversibly, or is impossible. (a) Qu = (500) kW, Oc = (100) kW %3D (b) Qu = (500)kW, Wey cycle (250)kW, Oc = (200)kW (c) Weycle = (350)kW, Oc = (150)kW (d) On = (500)kw, Oc = (100)kWAs shown in the figure below, two reversible cycles arranged in series each produce the same net work, Wcycle. The first cycle receives energy QH by heat transfer from a hot reservoir at TH = 1500°R and rejects energy Q by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy QC by heat transfer to a reservoir at TC = 450°R. All energy transfers are positive in the directions of the arrows. Determine:(a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles.(b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1500°R and 450°R, respectively. Also, determine the ratio of the net work developed by the single cycle to the net work developed by each of the two cycles, Wcycle.Q.2 A Carnot engine operates with ideal gas, using the Carnot cycle shown in the following Figure. Using the first law of thermodynamics and assume no change of internal energy, determine the thermal efficiency, the specific heat impute (q), and the work output (w) for each cycle of operation. (K=1.4 & R=0.287 KJ/Kg. K) T = 220 C 77 kPa T = 20 C 12 m'/kg
- As shown in the figure below, two reversible cycles arranged in series each produce the same net work, Wcycle. The first cycle receives energy QH by heat transfer from a hot reservoir at TH = 1000°R and rejects energy Q by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy Qc by heat transfer to a reservoir at Tc = 500°R. All energy transfers are positive in the directions of the arrows. Determine: Hot reservoir at TH QH Reservoir at T R1 lo ali R2 Qc Cold reservoir at Te W. cycle W cycle (a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles. (b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1000°R and 500°R. respectively. Also, determine the ratio of the net work developed by the single cycle to the net work developed by each of the two cycles, Wcycle.A heat engine An engine that converts power from heat operating at a steady-state receives energy by heat transfer at a rate of QH at TH = 1200 K and rejects energy by heat transfer to a cold reservoir at a rate Qc at Tc = 360 K. (i) Calculate the Carnot cycle efficiency (ii) For each of the following cases, analyze and determine whether the cycle operates reverslbly, operates İrreversibly, or is impossible. (a) QH = 720 kVW, Qc = 144 kW (b) QH = 720 kW, Wcycle = 360 kVW, Qc = 288 kW (c) Wcycle = 714 kW, Qc = 306 kW (d) QH = 920 kW, Qc = 368 kW Clearly show all steps of your calculations.As shown in the figure below, two reversible cycles arranged in series each produce the same net work, Weycle: The first cycle receives energy QH by heat transfer from a hot reservoir at TH = 1000°R and rejects energy Q by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature Tand rejects energy Qc by heat transfer to a reservoir at Tc = 450°R. All energy transfers are positive in the directions of the arrows. Hot reservoir at TH R1 W cycle Reservoir at T W cycle R2 Cold reservoir at Te Determine: (a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles. (b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1000°R and 450°R, respectively. Also, determine the ratio of the net work developed by the single cycle to the net work developed by each of the two cycles, Wcycle