A random sample of 240 adults over the age of 40 found that 144 would use an online dating service. Another random sample of 234 adults age 40 and under showed that 131 would use an online dating service. Assuming all conditions are met, which of the following is the standard error for a 90 percent confidence interval to estimate the difference between the population proportions of adults within each age group who would use an online dating service?     144240(1−144240)240+131234(1−131234)234−−−−−−−−−−−−−−−−−−√144240(1−144240)240+131234(1−131234)234 A 1.65144240(1−144240)240+131234(1−131234)234−−−−−−−−−−−−−−−−−−√1.65144240(1−144240)240+131234(1−131234)234 B 1.96144240(1−144240)240+131234(1−131234)234−−−−−−−−−−−−−−−−−−√1.96144240(1−144240)240+131234(1−131234)234 C 275474(1−275474)474−−−−−−−−√275474(1−275474)474 D 1.65275474(1−275474)474−−−−−−−−√1.65275474(1−275474)474 E

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
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A random sample of 240 adults over the age of 40 found that 144 would use an online dating service. Another random sample of 234 adults age 40 and under showed that 131 would use an online dating service. Assuming all conditions are met, which of the following is the standard error for a 90 percent confidence interval to estimate the difference between the population proportions of adults within each age group who would use an online dating service?

 
 
  • 144240(1−144240)240+131234(1−131234)234−−−−−−−−−−−−−−−−−−√144240(1−144240)240+131234(1−131234)234

    A
  • 1.65144240(1−144240)240+131234(1−131234)234−−−−−−−−−−−−−−−−−−√1.65144240(1−144240)240+131234(1−131234)234

    B
  • 1.96144240(1−144240)240+131234(1−131234)234−−−−−−−−−−−−−−−−−−√1.96144240(1−144240)240+131234(1−131234)234

    C
  • 275474(1−275474)474−−−−−−−−√275474(1−275474)474

    D
  • 1.65275474(1−275474)474−−−−−−−−√1.65275474(1−275474)474

    E
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