A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.67 hours, with a standard deviation of 2.39 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.14 hours, with a standard deviation of 1.99 hours. Construct and interpret a 95% confidence interval for the mean difference in leisure time between adults with no children and adults with children (u1 -u2). Let u, represent the mean leisure hours of adults with no children under the age of 18 and uz represent the mean leisure hours of adults with children under the age of 18. The 95% confidence interval for (u1 - H2) is the range from hours to hours. (Round to two decimal places as needed.)

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.2: Expected Value And Variance Of Continuous Random Variables
Problem 10E
icon
Related questions
Question
100%
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.67 hours, with a standard deviation of 2.39 hours. A
random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.14 hours, with a standard deviation of 1.99 hours. Construct and
interpret a 95% confidence interval for the mean difference in leisure time between adults with no children and adults with children (u1 - H2)
Let u, represent the mean leisure hours of adults with no children under the age of 18 and uz represent the mean leisure hours of adults with children under the age of
18.
The 95% confidence interval for (H1 - 42) is the range from hours to
hours.
(Round to two decimal places as needed.)
Transcribed Image Text:A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.67 hours, with a standard deviation of 2.39 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.14 hours, with a standard deviation of 1.99 hours. Construct and interpret a 95% confidence interval for the mean difference in leisure time between adults with no children and adults with children (u1 - H2) Let u, represent the mean leisure hours of adults with no children under the age of 18 and uz represent the mean leisure hours of adults with children under the age of 18. The 95% confidence interval for (H1 - 42) is the range from hours to hours. (Round to two decimal places as needed.)
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Point Estimation, Limit Theorems, Approximations, and Bounds
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Calculus For The Life Sciences
Calculus For The Life Sciences
Calculus
ISBN:
9780321964038
Author:
GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:
Pearson Addison Wesley,