A rock is dropped from the top of a building. Rock starts from rest and it takes 7 seconds to reach the ground. How far did the rock travel in 7 seonds. Ignore air drag and friction. Use g =9.8m/s2.

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A rock is dropped from the top of a building. Rock starts from rest and it takes 7 seconds to reach the ground. How far did the rock travel in 7 seonds. Ignore air drag and friction. Use g =9.8m/s2. (Don't round your answer). Choose correct answer with the correct unit.

  A.

240.1 m/s

  B.

240.1 m

  C.

34.3 m/s

  D.

34.3 m

Expert Solution
Step 1

Given: The initial speed of the rock is zero. 

           The time taken by the rock to reach the ground is 7 seconds. 

To determine: The distance the rock travel. 

The kinematic equation to calculate the distance is 

s=ut+12at2

where s is the distance, u is the initial speed, t is the time and a is the acceleration. 

Here, the rock is dropped from the top of a building thus, the acceleration is acceleration due to gravity (g). 

So, the equation becomes 

s=ut+12gt2 ................................. (1)

 

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