A sample of KHP, KHC8H&O4, weighing 2.035 g is titrated with NaOH and backtitrated with HCI. NaOH required = 23.20 mL; HCI required 2.675 mL. If each mL of HCI is equivalent () to 0.01600 g of Na20, what volume of 6.00 N NaOH must be added to 500 mL of above NaOH to bring it to 0.5000N? A sample of processed meat scrap weighing 4.000 g is digested with concentrated H2SO4 and Hg(catalyst) until the N present has been converted to NH&HSO4. This is treated with excess NaOH, and the liberated NH3 is caught in a 100-mL of H2SO4 ( 1mL 0.01860 g Na20). The excess acid requires 57.60 mL of NaOH ( ImL = 0.12660 g potassium acid phthalate, KHCBH4O4). Calculate the percentage protein in the meat scrap A 1.2 g sample of mixture of NaOH and NA2CO3 containing inert impurities s dissolved and titrated cold with 0.5N HCI. With phenolphthalein as indicator the solution turns colorless after the addition of 30.0 mL of the acid. Methyl orange is then added and 12 mL more of the acid is required before this indicator changes color. What is the percentage of NaOH and of Na2CO3 in the sample ?

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Chapter15: Acids And Bases
Section: Chapter Questions
Problem 15.100QP: A 2.500-g sample of a mixture of sodium carbonate and sodium chloride is dissolved in 25.00 mL of...
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3.
A sample of KHP, KHC8HAO4, weighing 2.035 g is titrated with NaOH and
backtitrated with HCI. NaOH required = 23.20 mL; HCI required = 2.675 mL. If
each mL of HCl is equivalent () to 0.01600 g of Na20, what volume of 6.00 N
NaOH must be added to 500 mL of above NAOH to bring it to 0.5000N?
4.
A sample of processed meat scrap weighing 4.000 g is digested with
concentrated H2SO4 and Hg(catalyst) until the N present has been converted to
NH&HSO4. This is treated with excess NaOH, and the liberated NH3 is caught in a
100-mL of H2SO4 ( 1mL = 0.01860 g Na2O). The excess acid requires 57.60 mL of
NaOH ( ImL = 0.12660 g potassium acid phthalate, KHCBH4O4). Calculate the
percentage protein in the meat scrap
A 1.2 g sample of mixture of NAOH and NazCO3 containing inert impurities s
dissolved and titrated cold with 0.5N HCI. With phenolphthalein as indicator the
solution turns colorless after the addition of 30.0 mL of the acid. Methyl orange is
then added and 12 mL more of the acid is required before this indicator
changes color. What is the percentage of NaOH and of Na2CO3 in the sample ?
5.
Transcribed Image Text:mixture? 3. A sample of KHP, KHC8HAO4, weighing 2.035 g is titrated with NaOH and backtitrated with HCI. NaOH required = 23.20 mL; HCI required = 2.675 mL. If each mL of HCl is equivalent () to 0.01600 g of Na20, what volume of 6.00 N NaOH must be added to 500 mL of above NAOH to bring it to 0.5000N? 4. A sample of processed meat scrap weighing 4.000 g is digested with concentrated H2SO4 and Hg(catalyst) until the N present has been converted to NH&HSO4. This is treated with excess NaOH, and the liberated NH3 is caught in a 100-mL of H2SO4 ( 1mL = 0.01860 g Na2O). The excess acid requires 57.60 mL of NaOH ( ImL = 0.12660 g potassium acid phthalate, KHCBH4O4). Calculate the percentage protein in the meat scrap A 1.2 g sample of mixture of NAOH and NazCO3 containing inert impurities s dissolved and titrated cold with 0.5N HCI. With phenolphthalein as indicator the solution turns colorless after the addition of 30.0 mL of the acid. Methyl orange is then added and 12 mL more of the acid is required before this indicator changes color. What is the percentage of NaOH and of Na2CO3 in the sample ? 5.
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