A ship arrives at the mouth of a river in water of density 1016 kg per cu. m with a freeboard of ‘S’ m. She then discharges 150 tonnes of cargo, and proceeds up river to a second port, consuming 14 tonnes of bunkers. When she arrives at the second port the freeboard is again ‘S’ m, the density of the water being 1004 kg per cu. m. Find the ship’s displacement on arrival at the second port.

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Question: Where did you get the 13,885.33 tonnes? Please provide explanations and can you illustrate the problem? Problem: A ship arrives at the mouth of a river in water of density 1016 kg per cu. m with a freeboard of ‘S’ m. She then discharges 150 tonnes of cargo, and proceeds up river to a second port, consuming 14 tonnes of bunkers. When she arrives at the second port the freeboard is again ‘S’ m, the density of the water being 1004 kg per cu. m. Find the ship’s displacement on arrival at the second port. Thank you so much. I am having a hard time to understand it an illustration and detailed explanation will be very helpful. Thank you.
Sebtion:
at mouth at riuen densi ty t uaten
on 24 pert
14 tonnes 4 bunkers Ship em sume
ISe tones dischange in Est port
be fore at 2 port toted weight dis change
= 150t14 (64 tones
hew displacement
old tisplacememt -weight dischenge
(* -164 ) tonnes
New deneity water -1004 kgm3
old displacement k
A =13885. 33 tonnes.
New
dispiacemont
=(12885 33-164) =137721 33 tones-
at second port displacement t
Ship - 13721- 33 tones
H displacement
= ldei New densi ty
ald tensi t
Weight dischanged
ol4 displacament
lo04
X-164
1o04 1 =
[-16 (x-164)
Transcribed Image Text:Sebtion: at mouth at riuen densi ty t uaten on 24 pert 14 tonnes 4 bunkers Ship em sume ISe tones dischange in Est port be fore at 2 port toted weight dis change = 150t14 (64 tones hew displacement old tisplacememt -weight dischenge (* -164 ) tonnes New deneity water -1004 kgm3 old displacement k A =13885. 33 tonnes. New dispiacemont =(12885 33-164) =137721 33 tones- at second port displacement t Ship - 13721- 33 tones H displacement = ldei New densi ty ald tensi t Weight dischanged ol4 displacament lo04 X-164 1o04 1 = [-16 (x-164)
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