A single point cutting tool with 0°rake angle is used in an orthogonal machining process. At a cutting speed of 180 m/min. the thrust force is 490 N. If the coefficient of friction between the tool and the chip is 0.7, then the power consumption (in kW) for the machining operation

A single point cutting tool with 0°rake angle is used in an orthogonal machining process. At a cutting speed of 180 m/min. the thrust force is 490 N. If the coefficient of friction between the tool and the chip is 0.7, then the power consumption (in kW) for the machining operation

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

For a turning operation, the cutting speed is 2.5 m/sec, and the depth of cut is 3 mm. A thrustforce of 300 N and cutting force of 400 N are measured. The tool rake angle is 10o and thecutting ratio r is 0.5. If Merchant theory applies, use the graphical method. Find the coefficientof friction between the chip and the tool. Also, the power consumed machining the material.
3. The machining time that required to turn a 0.20 m long shaft rotating at 300 rpm, at a tool feed of 0.20 mm/rev, is: 1 0.033 0.33 0.0033
Please
A pre-drilled hole of 010 mm in a block of 40 mm thick is required to be enlarged to O 16mm by core drilling process as shown in the figure below. The recommended cutting speed and the feed rate are 25 m/min. and 0.2 mm/rev respectively. The specific energy of block material is 4.0 W-s/mm³.Calculate the following a) Material removal rate (mm³/s) b) Power required for machining (W). c) Time required for machining. (Sec.) d) Total material removed (mm3) e) If the HSS core drill bit used obey the Taylor's tool life equation VT0.14 = 35 (m/min), how many holes the bit can enlarge before it is replaced? f) Is the above drilling operation can be done on an available drill press of 500 watts power with 80% efficiency? Check and show with calculation. o16 mm 40 mm H Fø10 mm Core drilling
A motorised metal guillotine machine is required to cut 45 mm diameter hole in a plate of 20 mm thickness at rate of 35 holes per minute. It requires a torque of 7 Nm for an area of hole in mm?. If the cutting takes 1/10 of a second and the speed of its flywheel varies from 165 rpm to 145 rpm, calculate: 4.1. Energy required to cut a hole. 4.2. Energy required for cutting work per second.
A motorised metal guillotine machine is required to cut 45 mm diameter hole in a plate of 20 mm thickness at rate of 35 holes per minute. It requires a torque of 7 Nm for an area of hole in mm2. If the cutting takes 1/10 of a second and the speed of its flywheel varies from 165 rpm to 145 rpm, calculate: 4.1. Energy required to cut a hole. 4.2. Energy required for cutting work per second. 43. Maximum fluctuation of energy of the flywheel. 4.4. Mass of the flywheel having radius of gyration of 1.5 m.
A motorised metal guillotine machine is required to cut 45 mm diameter hole in a plate of 20 mm thickness at rate of 35 holes per minute. It requires a torque of 7 Nm for an area of hole in mm2. If the cutting takes 1/10 of a second and the speed of its flywheel varies from 165 rpm to 145 rpm, calculate:4.1. Energy required to cut a hole.4.2. Energy required for cutting work per second.4.3. Maximum fluctuation of energy of the flywheel.4.4. Mass of the flywheel having radius of gyration of 1.5 m.
A motorised metal guillotine machine is required to cut 45 mm diameter hole in a plate of 20 mm thickness at rate of 35 holes per minute. It requires a torque of 7 Nm for an area of hole in mm². If the cutting takes 1/10 of a second and the speed of it's flywheel varies from 165 rpm to 145 rpm, calculate 4.1)Energy required to cut a hole 4.2)Energy required for cutting work per second. 4.3)Maximum fluctuation of energy of the flywheel 4.4)Mass of the flywheel having radius of gyrations of 1,5 m
We need to obtain the following part by OD operation in turning, starting from a 100mm diameter cylinder. The maximum allowable depth of cut is 3mm. It is required to make a finishing pass with d=1mm and a feed of 0.3mm/revolution. 150 mm 150 mm The machine has a total power of 10hp and 85% efficiency. The material has a specific energy 500 based on of 25 W/(cm³/min). It is recommended to make the operation at a constant rpm = calculations made for an average diameter. Determine the minimum required time to finish the part. Hint: calculate the maximum material removal rate then the cutting speed for each pass, then the feed rate for each pass and finally the time of cutting. 80 mm 100 mm
In a production operation, a high-speed steel face cutting tool with 8 cutting edges is used for the face milling of a rectangular workpiece with dimensions of 650 mm length x 120 mm width x 100mm thickness and 4 J/mm3 specific energy of cutting. The cutting tool has a diameter of 60 mm and is cutting with a rotational speed of 500 RPM and a chip load of 0.1 mm/tooth. If the part thickness is to be reduced to 95 mm using a 5 mm depth of cut and a width of cut of 40 mm, then find the following; a) The total time (min) to machine the workpiece b) Material removal rate during the cut c) The power (kw) consumed while the tool is engaged in cutting of the workpiece d) The Cutting force Fc
A student is using a lathe with 80-hp and 80% efficiency to fabricate a copper alloy with Sy = 1200ksi If the width of cut is 0.30 inand the student set a rake angle of 0and a cutting speed of 200fl / min while she assumed a coefficient of friction to be 0.5. What is the maximum depth of cut the student can achieve?
3. It is required to machine a slot with length 100 mm, width 15 mm, and depth 4 mm. Calculate the length and pitch of the broach assuming a super-elevation of 0.15 mm/tooth. Calculate the main power in KW if the specific cutting resistance is 2000 N/mm2 and the cutting speed of 10 m/min is used.