A solenoid has the following dimensions.inner diameter d = 4.92 cmlength L = 30.7 cmWhen a current flows through the coil of the solenoid, the magnetic field inside the solenoid is 4.20 T.(a) Determine the magnetic energy density (in J/m³) in the field.UB=Apply the equation for the magnetic energy density and insert values. J/m³(b) Determine the energy (in kJ) stored in the magnetic field within the solenoid.UB=Recall that the magnetic energy stored in the field equals u times the volume of the solenoid. kJ

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A solenoid has the following dimensions. inner diameter d = 4.92 cm length L = 30.7 cm When a current flows through the coil of the solenoid, the magnetic field inside the solenoid is 4.20 T. (a) Determine the magnetic energy density (in J/m³) in the field. 4B = X Apply the equation for the magnetic energy density and insert values. J/m³ (b) Determine the energy (in kJ) stored in the magnetic field within the solenoid. UB X Recall that the magnetic energy stored in the field equals u times the volume of the solenoid. kJ =

A solenoid has the following dimensions. inner diameter d = 4.92 cm length L = 30.7 cm When a current flows through the coil of the solenoid, the magnetic field inside the solenoid is 4.20 T. (a) Determine the magnetic energy density (in J/m³) in the field. 4B = X Apply the equation for the magnetic energy density and insert values. J/m³ (b) Determine the energy (in kJ) stored in the magnetic field within the solenoid. UB X Recall that the magnetic energy stored in the field equals u times the volume of the solenoid. kJ =

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter19: Magnetism

Section: Chapter Questions

Problem 63P: Ail electron is moving at a speed of 1.0 104 in/s in a circular path of radius 2.0 cm inside a...

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