A uniform rod is set up so that it can rotate about an axis at perpendicular to one of its ends. The length and mass of the rod are0.801 m and 1.25 kg, respectively. A force of constant magnitude F acts on the rod at the end opposite the rotation axis. Thedirection of the force is perpendicular to both the rod's length and the rotation axis.Calculate the value of F that will accelerate the rod from rest to an angular speed of 6.49 rad/s in 8.61 s.F =

Given:- The mass of the rod is m = 1.25 kg The length of the rod L = 0.801 m A force of constant…

A uniform rod is set up so that it can rotate about an axis at perpendicular to one of its ends. 0.801 m and 1.25 kg, respectively. A force of constant magnitude F acts on the rod at the en direction of the force is perpendicular to both the rod's length and the rotation axis. Calculate the value of F that will accelerate the rod from rest to an angular speed of 6.49 rad

A uniform rod is set up so that it can rotate about an axis at perpendicular to one of its ends. 0.801 m and 1.25 kg, respectively. A force of constant magnitude F acts on the rod at the en direction of the force is perpendicular to both the rod's length and the rotation axis. Calculate the value of F that will accelerate the rod from rest to an angular speed of 6.49 rad

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter8: Rotational Motion

Section: Chapter Questions

Problem 5STP

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