A volume of 500.0 mL of 0.110 M NaOH is added to 525 mL of 0.250 M weak acid (Ka = 2.53 × 10-). What is the pH of the%3Dresulting buffer?НА(аq) + ОН (aq).H,O(1) + A¯(aq)>pH

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A volume of 500.0 mL of 0.110 M NaOH is added to 525 mL of 0.250 M weak acid (K, = 2.53 × 10–5). What is the pH of the resulting buffer? НАаq) + ОН (аq) Н,О) + А (аq) > pH =

Chemistry for Engineering Students

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Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 12.71PAE: Acrylic acid is used in the polymer industry in the production of acrylates. Its K, is 5.6 X 10“’....

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A volume of 500.0 mL of 0.110 M NaOH is added to 525 mL of 0.250 M weak acid (Ka = 2.53 × 10-). What is the pH of the
%3D
resulting buffer?
НА(аq) + ОН (aq).
H,O(1) + A¯(aq)
>
pH

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