A W530x92 supports a uniformly distributed load of 12 kN/m (including the weight of the beam) and equal concentrated load P at quarter points (L/4, L/2, and 3L/4). The compression flange is laterally supported at quarter points and at the ends. The beam is 12m simply supported. Using A36 steel, the beam has the following properties: d = 533 mm %3D bf = 209 mm %3D tf = 15.6 mm tw 10.2 mm %3D k = 32 mm ry = 44.9 mm %3D Sx = 2070 x 10^3 mm^3 Zx = 2360 x 10^3 mm^3 Es = 200,000 MPa %3D Ix = 552 x 10^6 MPa Find the maximum allowable load P so that it will not exceed its maximum allowable moment capacity. Use conservative assumption for Cb. Consider all the necessary failure that could happen.

A W530x92 supports a uniformly distributed load of 12 kN/m (including the weight of the beam) and equal concentrated load P at quarter points (L/4, L/2, and 3L/4). The compression flange is laterally supported at quarter points and at the ends. The beam is 12m simply supported. Using A36 steel, the beam has the following properties: d = 533 mm %3D bf = 209 mm %3D tf = 15.6 mm tw 10.2 mm %3D k = 32 mm ry = 44.9 mm %3D Sx = 2070 x 10^3 mm^3 Zx = 2360 x 10^3 mm^3 Es = 200,000 MPa %3D Ix = 552 x 10^6 MPa Find the maximum allowable load P so that it will not exceed its maximum allowable moment capacity. Use conservative assumption for Cb. Consider all the necessary failure that could happen.

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter10: Plate Girders

Section: Chapter Questions

Problem 10.7.8P

See similar textbooks

Similar questions

Use "Unit Load method" & Mueller-Breslau Principle Please Influence Lines for: MA VA MB VB 0.5L 0.5L
Select an A992 (E= 345 MPa and Fu= 450 MPa) W-shape for the floor beam AB of the floor system shown. In addition to the weight of the beam, the service dead load consists of 125 mm thick reinforced concrete slab (we= 24 KN/m³). The service live load is 3.80 KPa and there is 0.95 KPa movable partition load. The total deflection (DL + LL) must not exceed L/240, where L is the length between supports. Use ASD tairder Flear Beam - Hax column Im overhang 4@1.5 m = 6 m
PROBLEM 2: The steel beam loaded below has the built-up cross section as shown. Determine the maximum permissible value of the load w so as not to exceed allowable bending stresses of 110 MPa. -125 mm- w (including beam weight) 20 mm 20 mm 100 mm .-- NA A B - 2 m - 6 m 20 mm FINAL ANSWER: Max. allowable w kN/m
How much service live load, in kN/m, can be supported? The member weight is the only dead load. The axial compressive load consists of a service dead load of 45 kN 6.2m and a service live load of 90 kN. Do not consider moment amplification. Use NSCP 2015. W460x144 а. LRFD. b. ASD. br te Sy Z,J wt A tw Ix Sx Ty Zx Cw SECTION kN/m mm? mm mm| mm3 mm mm mm3 mm3 mm3 mm mm mm mm mm mm W460x144 1.41 18400 472 13.6 283 22.2 | 726 3080 199 83.6 591 67.4 3450 906 2440 4230
5. The beam-column has a height of 7.5m and is a member of a braced frame. It is subjected to an axial load of DL-65KN and LL= 1OOKN. It is pinned at both ends. A W12X35 section was used and was made up of A-36 steel with Fy-250MPA. Compute the interaction value for beam- column based on NSCP 2015 code provisions. Ngelect the weight of the section. A = 6645 mm2 Zx- 839x10^3 mm3 d- 317.50mm Sx- 747x10^3 mm3 tw= 7.62 Rx= 133.35 bf= 166.62 ly= 10x10^6 mm4 tf- 13.21 Sy= 122x10^3 mm3 Ix= 119x10^6 mm4 Ry3 39.12mm 3.5 Note: Use C=D1.00%--0.2
1. Check the beam shown for compliance with the AISCS. Lateral support is provided only at the ends, and A992 steel (E345 MPa and Fu= 450 MPa). The only uniform service dead load is the weight of the beam. The 70 KN service loads are 30%DL and 70%LL. Use LRFD. IR₁ 0.90m 70,KN * W14 x 68 1.20m 70 KN * 0.90m R₂ W14x68 70 KN
How much service live load, in kN/m, can be supported? The member weight is the only dead load. The axial compressive load consists of a service dead load of 45 kN and a service live load of 90 kN. Do not consider moment amplification. Use NSCP 2015. a. b. LRFD. ASD. wt A kN/m mm² W460x144 1.41 18400 472 13.6 283 SECTION tw bf tf Ix Sx mm mm mm mm³ 22.2 726 3080 mm mm mm 199 6.2m W460x144 Sy Ty Zx ly mm mm³ mm 83.6 591 Zy J Cw mmº mm³ mm³ 67.4 3450 906 2440 4230 mmª
A rentengular beam having cross section of 250 mm x 400 mm (eff- depth) is reinforced with 4 Nos of 25 mm dia bar, find out Moment of resistance of the beam. Use M20 and fe 415
Select an A992 W-shape for beam AB of the floor system shown in Figure. In addition to the weight of the beam, the dead load consists of a 5-inch-thick reinforced concrete slab (normal-weight concrete). The live load is 80 psf, and there is a 20-psf partition load. The total deflection must not exceed L/240. a. Use LRFD. b. Use ASD
A simply supported beam is subjected to a uniform service dead load of 15kN/m(including the weight of the beam), a uniform service live load of 30kN/m. the beam is 12 meters long and is laterally supported at the midspan, and A572 Gr.50 steel is used. Is W30x108 adequate? Assume Cb=1 by 4 d fore k h h Z S Ly 267 TH mm 19.3 757 13.8 min m 35.8 685.4 54.6 737.7 5670 x10^3 4900 x103 mm 60.8 x10 6 mm 2080 x10 3 8300 x10^9 mm www
A W530x92 supports a uniformly distributed load of 12 kN/m (including the weight of the beam) and equal concentrated load P at quarter points (L/4, L/2, and 3L/4). The compression flange is laterally supported at quarter points and at the ends. The beam is 12m simply supported. Using A36 steel, the beam has the following properties: d = 533 mm bf = 209 mm tf = 15.6 mm tw = 10.2 mm k = 32 mm ry = 44.9 mm Sx = 2070 x 10^3 mm^3 Zx = 2360 x 10^3 mm^3 Es = 200,000 MPa Ix = 552 x 10^6 MPa Find the maximum allowable load P so that it will not exceed its maximum allowable moment capacity. Use conservative assumption for Cb.
Asap