A. Genotypic Analysis 1. The Problem 2. The Null Hypothesis The Distribution and Chi-square Testofthe Genotypes of the Beans Observed Frequency (0) Frequency (E) Еxpected Deviation Genotype Class (d =0 - E) d'/E Total Computed chi-square value Tabular chi-square value at dfand o.o5 levelofSignificance Decision
Activity 9GENES SEGREGATION BY BEAN-O TYPE Materials:
Colored beans to represent the gene for a certain trait of garden pea. (60 pieces of the same size and shape; 30 pieces of which are of different colors from rest)
Procedures:
1. Place the 30 pieces beans (one color) to one container and the other 30 pieces to the other container. Assign which color of beans will represent dominant and recessive genes of a specific trait of garden pea
2. Label the paper container as First Parent P1, male and other P1 female
3. At random, segregate the beans on the Lab table. Assume fertilization occurs and First filial generations (F1) are formed
4. Categorize the formed First filial generations
5. Put all the beans in one container. Assume that all the first filial generations undergo self-fertilization
6. Pick up the beans by two from the container without looking at it and collect the second Filial generation (F2)
7. Categorize the formed Second filial generations into two (2)
8. Fill up Table 15.1 for the genotypic result, and Table 15.2 for the phenotypic analysis
9. Compute for the Chi-Square Value and compare it with the Tabular Value
10. Interpret the results of your Chi-square test. Determine if null hypothesis is accepted or rejected
11. Diagram the cross showing segregation of genes influencing each phenotype or genotype
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