According to the ideal gas law, a 10.77 mol sample of oxygen gas in a 0.8345 L container at 496.0 K should exert a pressure of 525.3 atm. What is the percent difference betwe the pressure calculated using the van der Waals' equation and the ideal pressure? For O₂ gas, a = 1.360 L²atm/mol² and b = 3.183x10-2 L/mol. Percent difference = Pideal Pvan der Waals Pideal +Pean der Waals 2 x 100

Chemistry & Chemical Reactivity
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Chapter10: Gases And Their Properties
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Problem 53PS: In the text, it is stated that the pressure of 4.00 mol of Cl2 in a 4.00-L tank at 100.0 C should be...
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According to the ideal gas law, a 10.77 mol sample of oxygen gas in a 0.8345 L container at 496.0 K should exert a pressure of 525.3 atm. What is the percent difference betwe
the pressure calculated using the van der Waals' equation and the ideal pressure? For O₂ gas, a = 1.360 L²atm/mol² and b = 3.183×10-2 L/mol.
Percent difference
Pideal Pvan der Waals
Pideal +Puan der Waals
2
x 100
Transcribed Image Text:According to the ideal gas law, a 10.77 mol sample of oxygen gas in a 0.8345 L container at 496.0 K should exert a pressure of 525.3 atm. What is the percent difference betwe the pressure calculated using the van der Waals' equation and the ideal pressure? For O₂ gas, a = 1.360 L²atm/mol² and b = 3.183×10-2 L/mol. Percent difference Pideal Pvan der Waals Pideal +Puan der Waals 2 x 100
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