According to the Maxwell-Boltzmann law of theoretical physics, the pdf of V, the velocity of a gas molecule is given by Jkv? e-av? f,(v) = v > 0 elsewhere where a is a constant depending on its mass and the absolute temperature and k is 1 an appropriate constant. Show that the kinetic energy Y = - mv? is a random 2 variable having Gamma distribution.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.4: Plane Curves And Parametric Equations
Problem 44E
icon
Related questions
Question
According to the Maxwell-Boltzmann law of theoretical physics, the pdf of V,
the velocity of a gas molecule is given by
kv² e-av²
v > 0
f,(0) =
elsewhere
where a is a constant depending on its mass and the absolute temperature and k is
an appropriate constant. Show that the kinetic
energy
Y =
mV² is a random
variable having Gamma distribution.
Transcribed Image Text:According to the Maxwell-Boltzmann law of theoretical physics, the pdf of V, the velocity of a gas molecule is given by kv² e-av² v > 0 f,(0) = elsewhere where a is a constant depending on its mass and the absolute temperature and k is an appropriate constant. Show that the kinetic energy Y = mV² is a random variable having Gamma distribution.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer