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AH = 5.190 X 10-10 Tad + 2.813×10" Tod -3 + 7 492 X / 0³ Tad + 6.673 Tad -1977-0 answer is Tad = 185° C -

AH = 5.190 X 10-10 Tad + 2.813×10" Tod -3 + 7 492 X / 0³ Tad + 6.673 Tad -1977-0 answer is Tad = 185° C -

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Can you use the Newton-Raphson method for the answer.

T=183 degrees Celcius.  

AH = 5.190 X 10-¹0 Tad + 2.813×10" Tad -3 + 7.992 X/0³ Tad + 6.673 Tad -1977-0 answer is Tad = 185° C
Transcribed Image Text:AH = 5.190 X 10-¹0 Tad + 2.813×10" Tad -3 + 7.992 X/0³ Tad + 6.673 Tad -1977-0 answer is Tad = 185° C
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