A)It is required to use a multiplate clutch to transmit power of 24 kW at 1200 r.p.m If the clutch has the following data: • The Outer and inner plate radii are 120 mm and 80 mm respectively. • Maximum axial pressure pmax=0.12 N/mm?. • Coefficient of friction=0.3. Find: 1. The axial load (W) required. 2. The number of effective pairs of contact surfaces (n).

A)It is required to use a multiplate clutch to transmit power of 24 kW at 1200 r.p.m If the clutch has the following data: • The Outer and inner plate radii are 120 mm and 80 mm respectively. • Maximum axial pressure pmax=0.12 N/mm?. • Coefficient of friction=0.3. Find: 1. The axial load (W) required. 2. The number of effective pairs of contact surfaces (n).

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter7: Dry Friction

Section: Chapter Questions

Problem 7.76P: The clutch described in Prob. 7.75 is to transmit a torque of 120lbft when the total spring force...

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Q1/ A plate clutch having a single driving plate with contact surfaces on each side is required to transmit 110 kW at 1250 r.p.m. The outer diameter of the contact surfaces is to be 300 mm. The coefficient of friction is 0.4. (a) Assuming a uniform pressure of 0.17 N/mm? ; determine the inner diameter of the friction surfaces. (b) Assuming the same dimensions and the same total axial thrust, determine the maximum torque that can be transmitted and the maximum intensity of pressure when uniform wear conditions have been reach.
Q3 /A multi - plate clutch is to transmit 12 kW at 1500 r.p.m. The inner and outer radii for the plates are to be 50 mm and 100 mm respectively. The maximum axial spring forces is restricted to 1 kN. Answer the following questions 1- The necessary number of pairs of surfaces is u= 0.35 assuming constant wear. 2- The necessary number of pairs of surfaces is constant pressure. u= 0.18 assuming 3- The axial force 4- Percentage increase in forces is
Q. A multi plate clutch of alternate bronze and steel plates having effective diameters of 20 cm and 8 cm has to transmit 30 kW at 2000 r.p.m. The end thrust is 1.8 kN and coefficient of friction is 0.12. Calculate the number plates necessary, assuming uniform pressure distribution on the plates.
H.W (3): A multi-disc clutch has three discs on the driving shaft and two on the driven shaft. The outside diameter of the contact surfaces is 240 mm and inside diameter 120 mm. Assuming uniform wear and coefficient of friction as 0.3, find the maximum axial intensity of pressure between the discs for transmitting 25 kW at 1575 r.p.m. Ans. : p = 0.062 N/mm2
(b) A multiple plate clutch has more number of clutch plates. A typical clutch consist of the following important components which are drive (friction) plates and driven (steel) plates. If a multiple plate clutch with an effective diameter of 250 mm and 150 mm are able to transmit 60 kW at 1200 rpm. Also the end thrust is given as 4.5 kN and coefficient of friction is 0.13. Answer below questions; (i) Determine torque to be carry by friction clutch. (ii) Calculate number of plates required with uniform wear and uniform pressure theory. Compare your results.
A A multiple disc clutch transmits 55 kW of power at 1800 r.p.m. The coefficient of friction is 0.1 and the axial intensity of pressure is not to exceed 160 kN/m. The internal radius is 80 mm and is 0.7 times the external radius. Find the number of plates needed to transmit the required torque.
The following data relate to a cone clutch. The maximum and minimum surface contact radius are 150 mm and 125 mm respectively. Semi-cone angle = 20°, Allowable normal pressure is 14 x 10 N/m, coefficient of friction is 0.25. Find :(i) The axial load(ii) The power transmitted at a speed of 300 rpm.
H.W (1): A single dry plate clutch transmits 7.5 kW at 900 r.p.m. The axial pressure is limited to 0.07 N/mm:. If the coefficient of friction is 0.25, find 1. Mean radius and face width of the friction lining assuming the ratio of the mean radius to the face width as 4, and 2. Outer and inner radii of the clutch plate. Ans.: R = 113 mm , rl = 127.125 mm ; and 12 = 98.875
EXAMPLE(10) A multi plate clutch is to transmit 38KW at(9500) rpm. The inner and outer diameter were(14) &(20)cm .Take u =0.4 and the pressure on the friction plate as 350KN/m². CALCULATE the number of friction plate required.
Q. A multi disc clutch has 5 plates having four pairs Myd of active friction surfaces. If the intensity of pressure is not to exceed 127 kN/m?, find the power in kW transmitted at 500 r.p.m, if the outer and inner radii of friction surfaces are 125 mm and 75 mm respectively. Assume uniform wear and take coefficient of friction as 0.3.
Example: An automotive single-plate clutch with twe of friction Surfaces, transmits a 300 N-m to- pairs rque at 1500 rp.m. The inner and outer diameters of the friction disck are 170 and 270 mm The cofficient of friction is 0-35. The normal for- ce on the friction Surfaces is exerted by nine helical Compre ssion springs, so that the clutch is always engia- ged. The clutch is dis engaged when the external force Further Compresses (5) and the number of ac Five Coile are (6) The are made of patented and Cold-drawn steel respectively. the springs. The spring index is Springs wires of minimum tensile Stmength (MTS) (N/mm?)as Wive dia. 1 1-21-4 1.6 1-8 2 2.53 3.6445567 MTS, 1900 i2601817e0175017201640 1570 I510 1480 440 139013201260 NI mr The permissible shear stress for the wire is 30%. of the ultimate tensile strength, and (G-81370 Nimn). Design the springs and specily their dimensisns. Use this relatian to obtaine to the total normal fore required to transmit the torque. F= 4T where Dis…
H.W (2): A multiple disc clutch has five plates having four pairs of active friction surfaces. If the intensity of pressure is not to exceed 0.127 N/mm., find the power transmitted at 500 r.p.m. The outer and inner radii of friction surfaces are 125 mm and 75 mm respectively. Assume uniform wear and take coefficient of friction = 0.3. Ans. : Power =18800 W = 18.8 kW