Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is: 2 Al(s) + 3 Br2(1)=2 AIBr3(s) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) AIBr3(s) PAl(s) + 3/2 Br2(1) K1 = 2) Al(s) + 3/2 Br2(1) AlBr3(s) K, = 1/K 3) 2 AIBr3(s) 22 Al(s) + 3 Br2(1) K3 = Drag and drop your selection from the following list to complete the answer: (1/K)1/2 K1/2 1/K

Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is: 2 Al(s) + 3 Br2(1)=2 AIBr3(s) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) AIBr3(s) PAl(s) + 3/2 Br2(1) K1 = 2) Al(s) + 3/2 Br2(1) AlBr3(s) K, = 1/K 3) 2 AIBr3(s) 22 Al(s) + 3 Br2(1) K3 = Drag and drop your selection from the following list to complete the answer: (1/K)1/2 K1/2 1/K

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 2RQ: What is the law of mass action? Is it true that the value of K depends on the amounts of reactants...

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