An aluminum can is to be constructed to contain 2600 cm³ of liquid.Letr and h be the radius of the base and the height of the can respectively.a) Express h in terms of r. (If needed you can enter * as pi.)h =b) Express the surface area of the can in terms of r.Surface area =c) Approximate the value of r that will minimize the amount of required material (i.e. the value of r that will minimize the surface area).What is the corresponding value of h?T=h =

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An aluminum can is to be constructed to contain 2600 cm³ of liquid. Let r and h be the radius of the base and the height of the can respectively. a) Express h in terms of r. (If needed you can enter Tas pi.) h = 0 b) Express the surface area of the can in terms of r. Surface area = c) Approximate the value of r that will minimize the amount of required material (i.e. the value of r that will minimize the surface area). What is the corresponding value of h? T= h =

An aluminum can is to be constructed to contain 2600 cm³ of liquid. Let r and h be the radius of the base and the height of the can respectively. a) Express h in terms of r. (If needed you can enter Tas pi.) h = 0 b) Express the surface area of the can in terms of r. Surface area = c) Approximate the value of r that will minimize the amount of required material (i.e. the value of r that will minimize the surface area). What is the corresponding value of h? T= h =

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

ChapterA: Appendix

SectionA.2: Geometric Constructions

Problem 9P: A soda can is made from 40 square inches of aluminum. Let x denote the radius of the top of the can,...

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