An analytical chemist weighs out 0.165 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark with distilled water. He then titrates this solution with 0.1900 M NaOH solution. When the titration reaches the equivalence point, the chemist finds he has added 26.6 mL of NaOH solution. Calculate the molar mass of the unknown acid. Be sure your answer has the correct number of significant digits. 65.29 mol Correct Answer: 97.9 mol x10 X

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Chapter9: Acids, Bases, And Salts
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An analytical chemist weighs out 0.165 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark with distilled water. He then
titrates this solution with 0.1900M NaOH solution. When the titration reaches the equivalence point, the chemist finds he has added 26.6 mL of NaOH
solution.
Calculate the molar mass of the unknown acid. Be sure your answer has the correct number of significant digits.
65.29
mol
Correct Answer:
97.9
mol
☐x10
X
Transcribed Image Text:An analytical chemist weighs out 0.165 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark with distilled water. He then titrates this solution with 0.1900M NaOH solution. When the titration reaches the equivalence point, the chemist finds he has added 26.6 mL of NaOH solution. Calculate the molar mass of the unknown acid. Be sure your answer has the correct number of significant digits. 65.29 mol Correct Answer: 97.9 mol ☐x10 X
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