8. An electron is moving through a magnetic field in a direction perpendicular to the field as shown below.The charge is moving with a speed of v = 3.5 × 105 and it experiences a force of F =-S1.79 × 10-13 N. What is the magnitude and direction of the magnetic field? The charge of an electronis qe= = -1.6 × 10-19 C.v2F

Given: Speed of electron v=3.5×105 m/s (rightward or positive x axis), Force F=1.79×10-13 N…

An electron is moving through a magnetic field in a direction perpendicular to the field as shown below. The charge is moving with a speed of = 3.5 × 105 and it experiences a force of F = m S 1.79 × 10-13 N. What is the magnitude and direction of the magnetic field? The charge of an electron is qe = -1.6 x 10-1⁹ C. v 1 F

An electron is moving through a magnetic field in a direction perpendicular to the field as shown below. The charge is moving with a speed of = 3.5 × 105 and it experiences a force of F = m S 1.79 × 10-13 N. What is the magnitude and direction of the magnetic field? The charge of an electron is qe = -1.6 x 10-1⁹ C. v 1 F

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter11: Magnetic Forces And Fields

Section: Chapter Questions

Problem 23P: An electron moving at 4.00103 m/s in a 1.25-T magnetic field experiences a magnetic force of...

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