An extended aeration tank receives a BOD load of 768 kg/day. If two fixed aerators with oxygen transfer capacity of 0.8 kg of 02/HP hour are to be installed in aeration tank, what is the capacity of each aerator?
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- 5 ml wastewater is added to a 333 ml BOD flask. The initial dissolved O2 concentration was 13 mg/l and final dissolved O2 concentration was 4 mg calculate the BOD?As an operator of a wastewater treatment facility, you have learned that your plant runs well at an SRT (based on MLVSS (X) in the aeration basin) of 12 days. If today’s MLVSS (X) concentration is 2,700 mg/L and the RAS (Xr) concentration is 5,500 mg/L, how many L of sludge should you waste from the secondary clarifier today? Other design conditions: Average influent flow = 12,000 m3/d Influent soluble BOD = 150 mg/L Required effluent TSS = 30 mg/L Aeration tank Volume = 1,000 m3design an aeration tank of CASP based on the following data influent flowrate is 100000m3/d, influent CODcr is 200mg/l influent TKN is 40mg/l effluent is CODcr Is 20mg/l. required by Local regulation. Please answer very soon will give rating surely
- A cheese production facility in Winchester Ontario is having problems meeting the Provincial discharge limit of 25 mg/L BOD;. The facility produces and discharges 200 m³/d of wastewater with an influent concentration of 5,000 mg BODS /L. The current well mixed aerated lagoon has an operating volume of 10,000 m². What is the effluent concentration with the current system? What increase in volume is required to meet the discharge limit? The kinetic rate for BOD reduction is 0.5 d1. State any assumptions.• An average operating data for conventional activated sludge treatment plant is as follow:- • Wastewater flow =35000m³/d, volume of aeration tank =10900m2, influent BOD to aeration tank=162.5mg/l, effluent BOD=20mg/I, mixed liquor suspended solids32500mg/l. Based on the information above determine: - Aeration period, F/M, BOD load ,Percentage efficiency of BOD removal.Problem 2.Assume that DLSUD lake is 100m? and its average height is 5ft. Wastewater that flows into the lake are the following: Food square kitchen waste 5m³/hr; Total Dissolved Solids (TDS) is 50g/L which operates 8hrs per day b. CIH 5m³/hr kitchen waste; TDS is 20mg/L which operates 4hrs per day c. PCH 20m³/day diluted laboratory waste ; TDS = 40mg/L а. (1)Determine the volume of wastewater which DLSUD lake can still be contained without rainfall. (2)During operational hours a heavy rain fall, the rain gauge reading is 1.5m. Will the DLSUD Lake overflow? What is the volume of water that will over flow? (3). Compute the TDS concentration of the overflow.
- Problem 2.Assume that DLSUD lake is 100m² and its average height is 5ft. Wastewater that flows into the lake are the following: a. Food square kitchen waste 5m³/hr; Total Dissolved Solids (TDS) is 50g/L_which operates 8hrs per day b. CIH 5m³/hr kitchen waste; TDS is 20mg/L which operates 4hrs per day c. PCH 20m/day diluted laboratory waste ; TDS = 40mg/L (1)Determine the volume of wastewater which DLSUD lake can still be contained without rainfall. (2)During operational hours a heavy rain fall, the rain gauge reading is 1.5m. Will the DLSUD Lake overflow? What is the volume of water that will over flow? (3). Compute the TDS concentration of the overflow.na wastewater treatment plant, 35 mg/L of ammonia was nitrified to oxidized nitrogen in the bioreactor. The inflow is 2 ML/d. What is the minimum rate the A recycle must run at to achieve an effluent oxidized nitrogen of 2.5 mg/L? The RAS is run at a ratio of 1:1 sewage to RAS return. I need to know how to work out the answer pleaseX 1. One million gallons per day of municipal wastewater with a BOD5 of 260 mg/L and suspended solids of 220 mg/L are processed in a primary plus secondary activated- sludge plant. If the primary removal efficiencies for the BOD5 and TSS are 25% and 70%, respectively, then, the total sludge (in kg/day) which is removed by the primary clarifier every day is
- QUESTION: An aerated lagoon wastewater treatment is to be designed for a municipal wastewater. The design population is 5000 persons, and the aerated lagoon is to provide secondary treatment. Pertinent data are: flow = 380 L/cap-d, influent BOD5 = 255 mg/L; effluent BOD5 = 20 mg/L, K = 2.18 d-1 oxygen required 1.6 kg O2/kg BOD5 applied to the lagoons, and the primary clarifier removes 33 % of the influent BOD5. Calculate the total lagoon volume (m3)For an activated sludge basin with a flow rate of 500 L/s if the influent BOD5 = 100 mg/L, the MLVSS = 3000 mg/L and the volume of the aeration basin = 766100 gallons Find the F/M ratio If the WAS X= 10000 mg/L, find the WAS flowrate (m3/d)A municipal wastewater treatment plant processes an average of 14,000 m3 / day. The peak flow is 1.75 times the average. The wastewater contains 190mg/L BOD and 210 mg/L suspended solids at an average flow and 225 mg/L BOD and 365 mg/L suspended solids at peak flow. Determine the following for a primary clarifier with a 20-m diameter. Assume eff. BOD of 20 mg/L and effluent TSS of 30mg/L for average and peak flows. 1. Surface overflow rate and the approximate removal efficiency for BOD 5 and suspended solids @ average flow. 2. Surface overflow rate and the approximate removal efficiency for BOD 5 and suspended solids @ peak flow. 3. Mass of solids (kg/day) that is removed as sludge from average and peak flow conditions.