An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 680 mm. The cross-sectional dimensions of the beam are b, = 36 mm, d1 = 95 mm, b2 = 22 mm, d2 = 22 mm, and a = 7 mm. For this material, the allowable tensile bending stress is 11 MPa, and the allowable compressive bending stress is 13 MPa. Determine the largest moment M that can be applied as shown to the beam.
An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 680 mm. The cross-sectional dimensions of the beam are b, = 36 mm, d1 = 95 mm, b2 = 22 mm, d2 = 22 mm, and a = 7 mm. For this material, the allowable tensile bending stress is 11 MPa, and the allowable compressive bending stress is 13 MPa. Determine the largest moment M that can be applied as shown to the beam.
Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter6: Introduction To Mechanical Properties
Section: Chapter Questions
Problem 6.2P
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![An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 680 mm. The cross-sectional
dimensions of the beam are b, = 36 mm, d1 = 95 mm, b2 = 22 mm, d2 = 22 mm, and a = 7 mm. For this material, the allowable tensile
bending stress is 11 MPa, and the allowable compressive bending stress is 13 MPa. Determine the largest moment M that can be
applied as shown to the beam.
b2
a
M
d2
|d1
| A
B
L
b1
Answer:
M = i
N•m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F527d5a0a-3f35-4ff7-a0d6-4b07d9c672e0%2F4452d7d9-1732-4e34-9631-cc1462019583%2F5xzjqkd_processed.png&w=3840&q=75)
Transcribed Image Text:An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 680 mm. The cross-sectional
dimensions of the beam are b, = 36 mm, d1 = 95 mm, b2 = 22 mm, d2 = 22 mm, and a = 7 mm. For this material, the allowable tensile
bending stress is 11 MPa, and the allowable compressive bending stress is 13 MPa. Determine the largest moment M that can be
applied as shown to the beam.
b2
a
M
d2
|d1
| A
B
L
b1
Answer:
M = i
N•m
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