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- What does each removeMin call return within the following sequence of priority queue ADToperations:• insert(5, A),• insert(4, B),• insert(7, F),• insert(1, D),• removeMin( ),• insert(3, J),• insert(6, L),• removeMin( ),• removeMin( ),• insert(8, G),• removeMin( ),• insert(2, H),• removeMin( ),• removeMin( )? programming language : java• Complete the following table series of operations Method Return Value Priority Queue Contents Insert (5,A) Insert (7,B) Insert(9,D) Insert(8,C) Min() IsEmpty() RemoveMin() RemoveMin() isEmpty()Write a Python Code for the given function and conditions: (Use LinkedList Manipulation) Given function: def remove(self, deletekey) (4) Pre-condition: List is not empty. Post-condition: Removes the element from a list that contains the deleteKey and returns the deleted key value.
- True/False Select true or false for the statements below. Explain your answers if you like to receive partial credit. 3) Which of the following is true about the insertBeforeCurrent function for a CircularLinked List (CLL) like you did in programming exercise 1?a. If the CLL is empty, you need to create the new node, set it to current, andhave its next pointer refer to itselfb. The worst case performance of the function is O(n)c. If you insert a new element with the same data value as the current node, theperformance improves to O(log n)True or False For each statement below, indicate whether you think it is True or False. provide a description of your answer for partial credit in case you are incorrect. 3) Given a priority queue implemented as a standard linked list with only a head pointer, insert performing at O(n) and remove at O(1), and the following functions performed (higher numbers represent higher priorities): Insert(“Rick”, 75), Insert(“Carol”, 80), Insert(“Daryl”, 65), Remove(), Insert(“Negan”, 60), Insert(“Maggie”, 25), Remove(), Insert(“Michonne”, 55) a. If Insert(“Eugene”, 40) is called, it will be added as the last node in the linked list b. The linked list from head to the end at this point is Rick, Negan, Michonne, and then Maggie c. Carol was the first element removed from the priority queuePython program- implement a singly linked list with following functions: - add_head(e) - add_tail(e) - find_3rd_to_last() - returns element located at third-to-last in the list - reverse() - reveres the linked list, note, this is not just printing elements in reverse order, this is actually reversing the list
- Direction: Continue the code below and add case 4, case 5, and case 6. Add 3 more functions aside from insert, getValue, and clear from List ADT import java.util.LinkedList; import java.util.Scanner; class SampleLL { } public static void main(String[] args) { LinkedList 11s = new LinkedList(); String msg = "Choose a function: \n [1] Insert, [2]Get Value, [3]Clear, [0] Exit"; System.out.println(msg); Scanner scan= new Scanner(System.in); int choice scan.nextInt (); while(true) { } if (choice =0) { } System.exit(0); switch(choice) { } case 1: System.out.println("Enter a word/symbol:"); break; case 2: System.out.println("Enter a number: "); break; 11s.add(scan.next()); break; case 3 11s.clear(); default: System.out.println("Invalid input!"); break; System.out.println(11s.get (scan.nextInt())); System.out.println(msg); choice scan.nextInt ();Write a Python code using the given function and conditions. Do not use Numpy. Use LinkedList Manipulation. Given function: def insert(self, newElement, index) Pre-condition: The list is not empty. Post-condition: This method inserts newElement at the given index of the list. If an element with the same key as newElement value already exists in the list, then it concludes the key already exists and does not insert the key. [You must also check the validity of the index].The function interleave_lists in python takes two parameters, L1 and L2, both lists. Notice that the lists may have different lengths. The function accumulates a new list by appending alternating items from L1 and L2 until one list has been exhausted. The remaining items from the other list are then appended to the end of the new list, and the new list is returned. For example, if L1 = ["hop", "skip", "jump", "rest"] and L2 = ["up", "down"], then the function would return the list: ["hop", "up", "skip", "down", "jump", "rest"]. HINT: Python has a built-in function min() which is helpful here. Initialize accumulator variable newlist to be an empty list Set min_length = min(len(L1), len(L2)), the smaller of the two list lengths Use a for loop to iterate k over range(min_length) to do the first part of this function's work. On each iteration, append to newlist the item from index k in L1, and then append the item from index k in L2 (two appends on each iteration). AFTER the loop…
- Write method bodies of following methods: InsertinPriorityQ(int id) // This method will insert in priority queue. DelfromPriorityQ(int id) // This method will delete element from priority queue (Position given by user not from top) DelfromPriorityQ() //This method will delete element at top from priority queue. View() //This method will view all elements of priority queue Use array as a priority queue by making front and tail counters. Please don't use pointers. Code in C++8)A college has 5 departments, the total intake of each departments are 60, 76, 45, 80, 62 Use a sort technique that works by repeatedly stepping through the above intake values, and then enqueue the elements in a queue, one after another and display them.Write method bodies of following methods: (Use array of structure) InsertinPriorityQ(int id) // This method will insert in priority queue. DelfromPriorityQ(int id) // This method will delete element from priority queue (Position given by user not from top) DelfromPriorityQ() //This method will delete element at highest priority in queue. View() //This method will view all elements of priority queue isEmpty() isFull() Use ordered array as a ADT by making front and tail counters. Please don't use pointers. Code in C
