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- base 2 H3C H H3C OH heat H H3C + H₂O H The aldol reaction is a carbonyl condensation reaction between two carbonyl partners and involves a combination of nucleophilic addition and a-substitution steps. One partner is converted into an enolate ion nucleophile and adds to the electrophilic carbonyl group of the second partner. In the classic aldol reaction, the carbonyl partners are aldehydes or ketones, although aldehydes are more reactive. The product is a ẞ-hydroxy carbonyl compound. Under reaction conditions slightly more vigorous than those employed for the aldol reaction, the ẞ-hydroxyl group is eliminated in an E1CB dehydration to give an a,ẞ-unsaturated carbonyl compound. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions X :OH H₂O: а کی H₂C H H₂C H H2 Moin H3C H H₂C C⇒x= base :0: OH Hori H3C H. The aldol reaction is a carbonyl condensation reaction between two carbonyl partners and involves a combination of nucleophilic addition and a-substitution steps. One partner is converted into an enolate ion nucleophile and adds to the electrophilic carbonyl group of the second partner. In the classic aldol reaction, the carbonyl partners are aldehydes or ketones, although aldehydes are more reactive. The product is a B-hydroxy carbonyl compound. Under reaction conditions slightly more vigorous than those employed for the aldol reaction, the ß-hydroxyl group is eliminated in an E1cB dehydration to give an a,ß-unsaturated carbonyl compound. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions H₂C Ἡ :0: heat H Home H3C + H₂OI H H3C NOC XT :0: MET H₂C base H3C The aldol reaction is a carbonyl condensation reaction between two carbonyl partners and involves a combination of nucleophilic addition and a-substitution steps. One partner is converted into an enolate ion nucleophile and adds to the electrophilic carbonyl group of the second partner. In the classic aldol reaction, the carbonyl partners are aldehydes or ketones, although aldehydes are more reactive. The product is a ß-hydroxy carbonyl compound. H OH q H3C H₂C H Under reaction conditions slightly more vigorous than those employed for the aldol reaction, the ß-hydroxyl group is eliminated in an E1cB dehydration to give an a,ß-unsaturated carbonyl compound. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions heat H H + H₂O
- 2 CH3COOCH,CH3 C2H5O'K*/C2H5OH ---> CH3COCH,COOCH,CH3 [+] Hofmann elimination Clemmensen reduction Claisen condensation O Cannizzaro reaction O Aldol condensationMechanism of azide synthesis: Step 1: Nucleophilic substitution of alkyl halide with sodium azide to form an alkyl azide. Step 2: Reduction of alkyl azide with a reducing agent such as sodium borohydride or lithium aluminum hydride to form an alkylamine. Mechanism of alkylation of ammonia: Step 1: The alkyl halide undergoes a nucleophilic substitution reaction with ammonia gas to form an intermediate alkylamine. Step 2: The intermediate alkylamine is deprotonated by the catalyst to form the final alkylamine.Identify a type of reaction that can be used to prepare the compound below without the need for any further reactions. MeO O Conjugate addition O enolate alkylation O Claisen condensation O aldol reaction Submit Answ
- The Stork reaction is a condensation reaction between an enamine donor and an α,β-unsaturated carbonyl acceptor. The overall reaction consists of a three-step sequence of formation of an enamine from a ketone, Michael addition to an α,β-unsaturated carbonyl compound, and hydrolysis of the enamine in dilute acid to regenerate the ketone. Consider the Stork reaction between cyclohexanone and propenal Draw the structure of the product of the enamine formed between cyclohexanone and dimethylamine. - Michael addition to an α,β-unsaturated carbonyl compound, and - hydrolysis of the enamine in dilute acid to regenerate the ketone.Under basic conditions, in nucleophilic acyl substitution, O protonation of the carbonyl group is followed by nucleophilic attack. loss of the leaving group is followed by formation of an acylium ion. an SN2 mechanism is followed. the nucleophile must be a weaker base than the leaving group. O nucleophilic addition to the carbonyl is followed by loss of a leaving group.In a Wittig reaction, a ketone or aldehyde reacts as an electrophile with a nucleophile called a Wittig reagent (or phosphonium ylide) to produce an alkene. The Wittig reagent is commonly synthesized first in a two-step process beginning with an alkyl halide, then reacted with the carbonyl compound. In this problem, you'll explore the mechanism of a multi-step synthesis to make an alkene using the Wittig approach.
- Draw reaction mechanisms with all reactants, arrows, intermediates, and products. Your mechanism must account for all the products if more than one product is formed. 4-methycyclohexanol with phosphoric acid H3PO4 to for 1-methycyclohexene, 3- methylcyclohexene and 4-methycyclohexeneDraw the structures of the initially formed enol tautomers in the reactions of propyne and dicyclohexylethyne with dicyclohexylborane followed by NaOHNaOH and H2O2H2O2Draw the structure of the major aldol product (prior to possible dehydration) of the following reaction. CH3 + CH3 O CH3- are CH3 H You do not have to consider stereochemistry. If no reaction occurs, draw the organic starting material. Sn [F 5% NaOH 95% aq. ethanol, 30⁰ ?