Problem 5As shown in the figure, a very long straight wire carrying a current of I, is at a perpendiculardistance d = 11 cm from a point P. Point P is at the center of a circular arc of a radius R = 7cm that spans over an angle, and carries a current 1₂ H 13 A.12RPda)is B₁ = 0 +0 -1.09× 10-5 k T. Find I₁.1₁ =1₁The magnetic field vector at point P due to the straight wire onlyb)The magnetic field vector at point P due to the arc only is B₂ = 0 +0j+4.38x 105 & T. Find 0.0

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As shown in the figure, a very long straight wire carrying a current of I₁ is at a perpendicular distance d = 11 cm from a point P. Point P is at the center of a circular arc of a radius R = 7 cm that spans over an angle, and carries a current I₂ = 13 A. 1₂ 1₁ a) is B₁ = 0 +0 -1.09× 10-5k T. Find I₁. d = 1₁ The magnetic field vector at point P due to the straight wire only b) The magnetic field vector at point P due to the arc only is B₂ = 0 +03+ 4.38×105 T. Find 0.

As shown in the figure, a very long straight wire carrying a current of I₁ is at a perpendicular distance d = 11 cm from a point P. Point P is at the center of a circular arc of a radius R = 7 cm that spans over an angle, and carries a current I₂ = 13 A. 1₂ 1₁ a) is B₁ = 0 +0 -1.09× 10-5k T. Find I₁. d = 1₁ The magnetic field vector at point P due to the straight wire only b) The magnetic field vector at point P due to the arc only is B₂ = 0 +03+ 4.38×105 T. Find 0.