Assume we have a linked list of integer elements. Write a recursive method recNumEven (LLNode list) that returns the count of even numbers in the list. For example, assume values points to a list containing 19, 6, 6, 15, 12, 9, 18, 3, 20.Then, recNumEven (values) would return 5.
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- A consecutive sequence a list of numbers that are organized in increasing order with the next eleme. one bigger than the current. Write a non-recursive method "lengthConsec", which takes an IntNode myList as the parameter and returns the length of the consecutive sequence in myList. To simplify the implementation, you can assume that there is no more than one consecutive sequence in the list. For example, in the following linked list, the consecutive sequence begins at node "5" and ends at node "7", so lengthConsec (myList) should return 3 in this case. myList 8 13 4 public class IntNode { 12 private int m_data; private IntNode m_link; Consecutive sequence 6 7 28Given a singly linked list, reverse the list. This means you have to reverse every node. For example if there are 4 nodes, the node at position 0 will move to position 3, the node at 1 will move to position 2 and so on. You do not have to write the Node class just write what you have been asked to. You are NOT allowed to create a new list. In python languageWrite a method and test it to insert an array of elements at index in a single linked list and then display this list. The method receives this array and index by parameters. By using java language
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- Write a java method to search for an element in an array using a linear search. Many list processing tasks, including searching, can be done recursively. The base case typically involves doing something with a limited number of elements in the list (say the first element), then the recursive step involves doing the task on the rest of the list. Think about how linear search can be viewed recursively; if you are looking for an item in a list starting at index i:o ¬If i exceeds the last index in the list, the item is not found (return -1).o ¬If the item is at list[i], return i.o ¬If the is not at list[i], do a linear search starting at index i+1in java language import java.util.ArrayList;import java.util.Arrays; Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical order.*…test = true; ptrthis= llend if llend for if return false; llend for //end method