At a certain temperature, K. = 0.914 for the reaction NO,4) + NOg) N2OG) + O2) A mixture was prepared containing 0.200 mol of each gas in a 5.00 L container. What will be the equillibrium concentrations of each gas? [NO2] = M (NO] M. [N2O] M. (02) M How will the concentrations then change if 0.0500 mol of NO, is added to the equillbrium mixture? (NO2) M (NO) (N,O] (02) M

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter15: Principles Of Chemical Reactivity: Equilibria
Section15.3: Determining An Equilibrium Constant
Problem 15.3CYU: A solution is prepared by dissolving 0.050 mol of diiodocyclohexane, C5H10I2, in the solvent...
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At a certain temperature, K. = 0.914 for the reaction
NO23) + NO(3)
N20(3) + O23)
A mixture was prepared containing 0.200 mol of each gas in a 5.00 L container.
What will be the equilibrium concentrations of each gas?
[NO2] = i
[NO]
[N2O]
M
M.
How will the concentrations then change if 0.0500 mol of NO, is added to the equilibrium mixture?
[NO2)
[NO]
i
%3D
[N2O]
%3D
[02]
i
%3D
Transcribed Image Text:At a certain temperature, K. = 0.914 for the reaction NO23) + NO(3) N20(3) + O23) A mixture was prepared containing 0.200 mol of each gas in a 5.00 L container. What will be the equilibrium concentrations of each gas? [NO2] = i [NO] [N2O] M M. How will the concentrations then change if 0.0500 mol of NO, is added to the equilibrium mixture? [NO2) [NO] i %3D [N2O] %3D [02] i %3D
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