(b) Is the motion of the rock one with constant velocity or constant acceleration?+Choose an appropriate equation of motion to calculate the height of the cliff.Something to think about: Do you need to split the trip into two parts: 1. the rock's journey up, and2. the rock's journey down? Is it possible to solve without splitting the motion into two parts?Ay = vtAy = (v₁ + v)2V = V₁ + at✓²=²+2aAyAy=vot+ = at²(c) Calculate the height of the cliff. Note: The height of the cliff should be a positive value.Enter to 3 significant figuresh=✔m(d) How long would it take the rock to reach the ground if it is thrown straight down with the samespeed instead of up?Enter to 3 significant figurest=✔SSense-making: Check if the answer in part (d) is less than the time in part (a). 1. The solution to Part 1 should have looked like this.Consider the sketch below. Adjust the colored sliders so that the correspondingvo, V, and a vectors are oriented in the correct directions.a =Top of clifft=YoY✔m/s✔m/s²✔ SVO↓.aBottom of cliffYVoIt takes 2 s for a rock to hit the ground when it is thrown straight up from a cliff with an initial velocityof 7.00 m/s. Assume all values are correct upto 3 significant figures.V(a)• Using the notation Ay=y-yo for displacement, y for position after time t, yo for the initialposition, v for velocity after time t, vo for initial velocity, and a for acceleration, determinewhat quantities are known and what are unknown.• Enter the values of some known quantities below.• Make sure you account for the signs of the vectors using the coordinate system used inPart 1.Enter to 3 significant figuresVo =a

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Description: (b) Is the motion of the rock one with constant velocity or constant acceleration?+Choose an appropriate equation of motion to calculate the height of the cliff.Something to think about: Do you need to split the trip into two parts: 1. the rock's jo

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(b) Is the motion of the rock one with constant velocity or constant acceleration? Choose an appropriate equation of motion to calculate the height of the cliff. Something to think about: Do you need to split the trip into two parts: 1. the rock's journey up, and 2. the rock's journey down? Is it possible to solve without splitting the motion into two parts? Ay=vt Ay = (vo+ v)₁ t 2 v=v₁ + at ✓= √²+2aAy 1 Ay= Vot+2 -at² (c) Calculate the height of the cliff. Note: The height of the cliff should be a positive value. Enter to 3 significant figures h= t= m (d) How long would it take the rock to reach the ground if it is thrown straight down with the same speed instead of up? Enter to 3 significant figures S Sense-making: Check if the answer in part (d) is less than the time in part (a).

(b) Is the motion of the rock one with constant velocity or constant acceleration? Choose an appropriate equation of motion to calculate the height of the cliff. Something to think about: Do you need to split the trip into two parts: 1. the rock's journey up, and 2. the rock's journey down? Is it possible to solve without splitting the motion into two parts? Ay=vt Ay = (vo+ v)₁ t 2 v=v₁ + at ✓= √²+2aAy 1 Ay= Vot+2 -at² (c) Calculate the height of the cliff. Note: The height of the cliff should be a positive value. Enter to 3 significant figures h= t= m (d) How long would it take the rock to reach the ground if it is thrown straight down with the same speed instead of up? Enter to 3 significant figures S Sense-making: Check if the answer in part (d) is less than the time in part (a).

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter3: Vectors

Section: Chapter Questions

Problem 1PQ: A velocity vector has a magnitude of 720 m/s. Two students draw arrows representing this vector....

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