B1, (i) A domestic lighting installation having 25, 75 W lamps is operated as follows: 7 lamps 6 Pm till 8 pm 12 lamps 8 pm till 10 pm 3 lamps 10 pm till 11.45 pm Determine the demand factor and monthly load factor. Demand factor DF= Daily load factor, LF =
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- 7. A power station has to meet the following load demand : 50 kW Load A between 10 A.M. and 6 P.M. Load B 30 kW between 6 P.M. and 10 P.M. Load C 20 kW between 4 P.M. and 10 A.M. Plot the daily load curve and determine (f) diversity factor () units generated per day (üi) load factor. () 1-43 () 880 kWh (i) 52-38%]Fill in the table for a correctly wired duplex outlet (U.S. National Electric Code standards for voltage PARAMETER EQUATION and frequency). Note the used of double- subscript notation. You can assume a 0° phase reference for Vba(t). Vba(t) Vea(t) Vbe(t) Vba (Peak Phasor) Vea (Peak Phasor) Vbc (Peak Phasor) Vba (RMS Phasor) Vea (RMS Phasor) Vbc (RMS Phasor) A C7. A power station has to meet the following load demand: Load A 50 kW between 10 A.M. and6 P.M. Load B 30 kW between 6 P.M. and 10 P.M. Load C 20 kW between 4 P.M. and 10 A.M. Plot the daily load curve and determine (i) diversity factor (ii) units generated per day (iii) load factor. () 1-43 (ii) 880 kWh (iii) 52-38%]
- The annual load of a substation is given in the following table. During each month, the power is assumed constant at an average value. In the HTML editor below, write the MATLAB codes and the barcycle function to obtain a plot of the annual load curve. (Also write the necessary statements to find the average load and the annual load factor.) Annual System Load Interval, month Load, MW January February 8 6 Маrch 4 April Мay 2 June 12 July August September October 16 14 10 4 November 6. December 8Khalid Abdulrahman Abdullah Alqasmi KA 05 Symm... 9 Search 8 Share O Comments Transitions Animations Slide Show Review View Help 1. A 3- phase, 30 MVA, 33 KV alternator has internal reactance of 4% and negligible resistance. Find the external reactance per phase to be connected in series with the alternator so that steady current on short circuit does not exceed 10 times the full load. Also find Find the full load current. d notesA 250V, 50 Hz single-phase supply feeds the following loads (i) incandescent lamps taking a current of 10A at unity power factor, (ii) fluorescent lamps taking 8A at a power factor of 0.7 lagging, (iii) a 3 kVA motor operating at full load and at a power factor of 0.8 lagging, and (iv) a static capacitor. Determine, for the lamps (incandescent and fluorescent) and motor, (a) the total current, (b) the overall power factor, and (c) the total power. (d) Find the value of the static capacitor to improve the overall power factor to 0.975 lagging.
- The variation of the load is considered over a period of month in the monthly load curve. Select one: True FalseA synchronous generator has been synchronized to an infinite grid of 13.8 kV and 60 Hz. The generator prime mover C/C is such that the no-load frequency is 62.5 Hz and the power slope is 1 MW/Hz. The AVR C/C (The reactive power against the terminal voltage C/C) is such that the zero reactive power voltage is 14.6 kV, while the slope is 0.4 MVAR/kV. Calculate: (a) the kVA loading of the generator and its power factor. (b) the settings of the prime mover and AVR such that the generator delivers 3 MW at 0.85 lagging power factor.The peak load on a 50 MW power station is 39 MW. It supplies power through for transformers whose connected loads are 17, 12,9 and 10 MW. The maximum demands on these transformers are 15, 10, 8 and 9 MW respectively. The annual load factor is 50% and the plant is operating for 65% of the period in a year. 102. The average load on the station is (A) 50000 kW (C) 39000 kW (B) 19500 kW (D) 48000 kW. 103. The energy supplied per year is (A) 438 x 106 kWh (C) 170.82 x 106 kWh (B) 341.64 x 106 kWh (D) 420.48 x 106 kWh.
- A generation station has maximum demand of 10,000KW, the daily demand as following, calculate the daily load factor. 11 pm to 6 am 6 am to 8 am 8 am to 12 noon 12 noon to 1 pm 1 pm to 5 pm 5 pm to 7 pm 7 pm to 9 pm pm to 11 pm 9 DR. MOHAMED RAGAB ABOELMAGD Time 00-5 MW The daily demand various as following table, calculate daily load factor. 5~7 7-8 8-12 1 4 0.1 2 2,000 Kw 3,500 Kw 8,000 kw 3,000 kw 7,500 Kw 8,500 kw 10,000 kw 4,500 kw DR. MOHAMED PAGAR ABOFLMAGD 12-14 14-18 18-21 21-24 1 4 6 0.6 10Problem 3 A climate control system, a motor load, and a lightning circuit of a small warehouse establish a 20- kVA power demand at 0.587 power factor lagging on a 240 V, 60 Hz supply. a) Establish the power triangle for the load. b) Determine the power-factor capacitor that must be placed in parallel with the load to raise the power factor to 0.865 lagging. c) Determine the change in supply current from the uncompensated to the compensated system. Explain.In the case of reactive power compensation in a low voltage distribution network and increasing the power factor to cosQ2 = 0.92 as a result of compensation while cosQ1 = 0.75, which of the following expresses the change in apparent power transmitted from the line a) increase by 22.66% b) decrease by 22.66% c) increase by 18.47% d) increase by 15.00% e) decrease by 18.47%