Base 16 Base 8 Base 10 2. Base 2 1. 3. 11000111.111101
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- 6-In the representation Complement to 1, we the number when Code the absolute value thus is negative: A = True B- False 7- The result in base 10' A - 44.25 B-42015 C- 51. 13 45. 75 8- The result AT 40. B + 61 q of the transformation (101001.10) 2 usi o the transformation (52) a in bose 10 is: C² 42 D-41 WWW 30 O5. Convert the decimal number 45.5 to IEEE 754 32-bit single precision floating point binary format. 01000010001101110000000000000000 01000010001101100000000000000000 01000010101101100000000000000000 01010010001101100000000000000000 01000010001101100100000000000000 01000010001101101100000000000000 11000010001101100001000000000000 11000010001101100000000000000000 01011010001101100000000000000000Find the representation x of the following signed numbers listed below in the base specified on the right; 1.- (01100110)2=(x )10 2.- (10110111)2=( x )10 3.- (207)10=( x )2 4.- (-135)10=( x )2 5.- (2D7)16=( x )2 6.- (10110011)2=(x )16 7.- (-5.5)10=( x )2 8.- (11000001010000000000000000001010)2=( x )10 Note: In question 8 the binary representation on the left corresponds to a real number representation.
- 1165:0100 B84518 1165:0103 BB3478 1165:0106 01C3 1165:0108 48 1165:0109 4B 1165:010A 891E0001 1165:010E CD20 MOV MOV ADD AX, 1845 BX,7834 BX, AX DEC AX DEC MOV BX (0100], BX INT 20 You have used DEBUG to unassemble the above code. The entire program is bytes long. 8 16 64 010E 1165Convert the following numbers into base ten. (a) 32five (b) 22six (c) 410five (d) 3203five (e) 202five (f) 1222six (g) 202four (h) 404seven (i) 1000two (j) 11011two (k) 88sixteen (l) 707sixteen ?Complete the Lesson with Eight LEDs with 74HC595. This code uses a shift register to use a single data pin to light up 8 LEDs. Run the code with the loop() replaced with void loop () { } leds = 0b00001111; Serial.println(leds); 00 digitalWrite (latchPin, LOW); shiftOut (dataPin, clock Pin, MSBFIRST, leds); digitalWrite (latchPin, HIGH); delay (1000); Which LED lights are turned on? QA QB QC QD QE QF QG QH
- calculate the unit roots of those data using R studio. Corn Soybeans 107.3439992 212.1854389 119.9418335 223.3474526 109.0499573 224.0288101 100.7826335 216.8401058 106.9503123 210.3174476 107.0264359 211.8026538 108.2339452 207.8063774 107.6806234 205.1881272 113.3974024 211.9710793 109.4783249 218.68513 99.38355509 204.6216053 94.59194946 203.9325921 95.29482524 212.1624718 97.47875214 220.3617288 101.0777537 247.1796532 114.3085302 240.8483875 123.4909185 251.9414999 112.0336965 247.5318155 97.49782817 215.0716386 98.09031677 203.4962171 107.8345006 205.1651601 113.8585027 213.1883359 128.0398865 226.1417838 144.0723724 251.5663705 164.1147054 268.049097 196.5570933 290.1817318 176.5597483 294.185664 120.8602168 257.4153269 122.7673162 284.8380517 118.6350199 312.6588731 110.2028834 267.9878514 117.0844472 256.9253619 113.9421438 244.5154688 104.8021596 234.1190254 91.6590449 209.3375178 96.06801605…You are hired to decrypt a message that has the following binary sequence: 0100 0101 0100 1100 0100 0011 0110 1111 0110 0100 0110 1001 0100 0111 0110 1111 0100 0101 0101 0011 0011 0011 0011 0111 0011 0101 0011 0001 0011 0110 0011 0010 The message must be displayed on a 7-segment display, it is only known that the encoding is in ASCII. 1.Approach, encoding of the message and truth table. 2.Functional electronic circuit to display the message.When Ox0A0B0304 is stored within the address starting Ox0100 on a computer using big-Endian order, what does the address Ox0102 have? 03 OB 30 BO