Based on the above, find the general solution of the following differential equation y""-y" - 2y' = (100x - 25) cos2x, y = y(x).

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Chapter2: Second-order Linear Odes
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EXERCISE 5
The method of determinable coefficients for finding a solution of a non-homogeneous linear ordinary differential
equation with constant coefficients can be applied when the non-homogeneous term f(x) of the equation has the form:
f(x) = ex [Pm(x)cos(bx)+Q:(x)sin(bx)],
where a, beR and Pm(x), Q(x) polynomials of x degree m and r respectively. In this case the o.d.e. that we want to
solve is amenable to a solution of the form:
yu(x)=x³ex [R₂(x)cos(bx)+T:(x)sin(bx)],
where s=max{m,r}, R.(x),T:(x) are complete polynomials of x degrees whose coefficients are to be determined and
is the multiplicity with which the number a+bi appears as a root of the characteristic equation of the corresponding
homogeneous o.d.e.
(Consequently, if a+bi is not a root of the corresponding characteristic equation, then = 0, if it is a simple root then
π = 1, if it is a double root then -2, and so on).
In the more special case where the non-homogeneous o.d.e. has the form
y() (x)+ay(n-1)(x)+...+an-ky)(x) = f(x) (1)
where, an-k+1=..=an-1-an=0 and f(x)=20x² +21x²-¹+...+2μu-Ix+u, then to find a partial solution of (1) we set
yk)(x) = box+bx-1+...+bu-ix+bu and calculate the coefficients bi, ie{0,1,...,}.
Then with k-successive integrations we calculate the partial solution of (1).
Based on the above, find the general solution of the following differential equation
y"-y" - 2y' = (100x - 25) cos2x,
y = y(x).
Transcribed Image Text:EXERCISE 5 The method of determinable coefficients for finding a solution of a non-homogeneous linear ordinary differential equation with constant coefficients can be applied when the non-homogeneous term f(x) of the equation has the form: f(x) = ex [Pm(x)cos(bx)+Q:(x)sin(bx)], where a, beR and Pm(x), Q(x) polynomials of x degree m and r respectively. In this case the o.d.e. that we want to solve is amenable to a solution of the form: yu(x)=x³ex [R₂(x)cos(bx)+T:(x)sin(bx)], where s=max{m,r}, R.(x),T:(x) are complete polynomials of x degrees whose coefficients are to be determined and is the multiplicity with which the number a+bi appears as a root of the characteristic equation of the corresponding homogeneous o.d.e. (Consequently, if a+bi is not a root of the corresponding characteristic equation, then = 0, if it is a simple root then π = 1, if it is a double root then -2, and so on). In the more special case where the non-homogeneous o.d.e. has the form y() (x)+ay(n-1)(x)+...+an-ky)(x) = f(x) (1) where, an-k+1=..=an-1-an=0 and f(x)=20x² +21x²-¹+...+2μu-Ix+u, then to find a partial solution of (1) we set yk)(x) = box+bx-1+...+bu-ix+bu and calculate the coefficients bi, ie{0,1,...,}. Then with k-successive integrations we calculate the partial solution of (1). Based on the above, find the general solution of the following differential equation y"-y" - 2y' = (100x - 25) cos2x, y = y(x).
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